# Graeco-Latin square

Graeco-Latin square  Orthogonal Latin squares of order 3  Orthogonal Latin squares of order 5

In mathematics, a Graeco-Latin square or Euler square or orthogonal Latin squares of order n over two sets S and T, each consisting of n symbols, is an n×n arrangement of cells, each cell containing an ordered pair (s,t), where s is in S and t is in T, such that every row and every column contains each element of S and each element of T exactly once, and that no two cells contain the same ordered pair.

The arrangement of the Latin characters alone and of the Greek characters alone each forms a Latin square. A Graeco-Latin square can therefore be decomposed into two "orthogonal" Latin squares. Orthogonality here means that every pair (st) from the Cartesian product S×T occurs exactly once.

## History

Orthogonal Latin squares have been known to predate Euler. As described by Donald Knuth in Volume 4 of TAOCP, the construction of 4x4 set was published by Jacques Ozanam in 1725 (in Recreation mathematiques et physiques) as a puzzle involving playing cards. The problem was to take all aces, kings, queens and jacks from a standard deck of cards, and arrange them in a 4x4 grid such that each row and each column contained all four suits as well as one of each face value. This problem has several solutions.

A common variant of this problem was to arrange the 16 cards so that, in addition to the row and column constraints, each diagonal contains all four face values and all four suits as well. As described by Martin Gardner in Gardner's Workout, the number of distinct solutions to this problem was incorrectly estimated by Rouse Ball to be 72, and persisted many years before it was shown to be 144 by Kathleen Ollerenshaw. Each of the 144 solutions has 8 reflections and rotations, giving 1152 solutions in total. The 144x8 solutions can be categorized into the following two classes:

Solution Normal form
Solution #1 A♠ K♥ Q J♣
Q♣ J A♥ K♠
J♥ Q♠ K♣ A
K A♣ J♠ Q♥
Solution #2 A♠ K♥ Q J♣
J Q♣ K♠ A♥
K♣ A J♥ Q♠
Q♥ J♠ A♣ K

For each of the two solutions, 24x24 = 576 solutions can be derived by permuting the four suits and the four face values independently. No permutation will convert the two solutions into each other.

The solution set can be seen to be complete through this proof outline:

1. Without loss of generality, let us choose the card in the top left corner to be A♠.
2. Now, in the second row, the first two squares can be neither ace nor spades, due to being on the same column or diagonal respectively. Therefore, one of the remaining two squares must be an ace, and the other must be a spade, since the card A♠ itself cannot be repeated.
3. If we choose the cell in the second row, third column to be an ace, and propagate the constraints, we will get Solution #1 above, up to a permutation of the remaining suits and face values.
4. Conversely, if we choose the (2,3) cell to be a spade, and propagate the constraints, we will get Solution #2 above, up to a permutation of the remaining suits and face values.
5. Since no other possibilities exist for (2,3), the solution set is complete.

### Euler's work and conjecture

Orthogonal Latin squares were studied in detail by Leonhard Euler, who took the two sets to be S = {ABC, …}, the first n upper-case letters from the Latin alphabet, and T = {α , β, γ, …}, the first n lower-case letters from the Greek alphabet—hence the name Graeco-Latin square.

In the 1780s Euler demonstrated methods for constructing Graeco-Latin squares where n is odd or a multiple of 4. Observing that no order-2 square exists and unable to construct an order-6 square (see thirty-six officers problem), he conjectured that none exist for any oddly even number n ≡ 2 (mod 4). Indeed, the non-existence of order-6 squares was definitely confirmed in 1901 by Gaston Tarry through exhaustive enumeration of all possible arrangements of symbols. However, Euler's conjecture resisted solution for a very long time.

### Counterexamples to the conjecture of Euler

In 1959, R.C. Bose and S. S. Shrikhande constructed some counterexamples (dubbed the Euler spoilers) of order 22 using mathematical insights. Then E. T. Parker found a counterexample of order 10 through computer search on UNIVAC (this was one of the earliest combinatorics problems solved on a digital computer).

In 1960, Parker, Bose, and Shrikhande showed Euler's conjecture to be false for all n ≥ 10. Thus, Graeco-Latin squares exist for all orders n ≥ 3 except n = 6.

## Applications

Graeco-Latin squares are used in the design of experiments, tournament scheduling and constructing magic squares. The French writer Georges Perec structured his 1978 novel Life: A User's Manual around a 10×10 orthogonal square.

## Mutually orthogonal Latin squares

Mutually orthogonal Latin squares arise in various problems. A set of Latin squares is called mutually orthogonal if every pair of its element Latin squares is orthogonal to each other.

 fjords jawbox phlegm qiviut zincky zincky fjords jawbox phlegm qiviut qiviut zincky fjords jawbox phlegm phlegm qiviut zincky fjords jawbox jawbox phlegm qiviut zincky fjords

The above table shows 4 mutually orthogonal Latin squares of order 5, representing respectively:

Due to the Latin square property, each row and each column has all five texts, all five foregrounds, all five backgrounds, and all five typefaces.

Due to the mutually orthogonal property, there is exactly one instance somewhere in the table for any pair of elements, such as (white foreground, monospace), or (fjords, navy background) etc., and also all possible such pairs of values and dimensions are represented exactly once each.

The above table therefore allows for testing 5 values each of 4 different dimensions in only 25 observations instead of 625 observations. Note that the five 6-letter words (fjords, jawbox, phlegm, qiviut, and zincky) between them cover all 26 letters of the alphabet at least once each. The table therefore allows for examining each letter of the alphabet in five different typefaces, foreground colors, and background colors.

Due to a close relation between orthogonal Latin squares and combinatorial designs, every pair of distinct cells in the 5x5 table will have exactly one of the following properties in common:

• a common row, or
• a common column, or
• a common text, or
• a common typeface, or
• a common background color, or
• a common foreground color.

In each category, every cell has 4 neighbors (4 neighbors in the same row with nothing else in common, 4 in the same column, etc.), giving 6 * 4 = 24 neighbors, which makes it a complete graph with 6 different edge colors.

### The number of mutually orthogonal latin squares

The number of mutually orthogonal Latin squares that may exist for a given order n is not known for general n, and is an area of research in combinatorics. It is known that the maximum number of MOLS for any n cannot exceed (n-1), and this upper bound is achieved when n is a power of a prime number. The minimum is known to be 2 for all n except for n = 1, 2 or 6, where it is 1. For general composite numbers, the number of MOLS is not known. The first few values starting with n = 2, 3, 4... are 1, 2, 3, 4, 1, 6, 7, 8, ... (sequence A001438 in OEIS).

## Bibliography

• Raghavarao, Damaraju (1988). Constructions and Combinatorial Problems in Design of Experiments (corrected reprint of the 1971 Wiley ed.). New York: Dover.
• Raghavarao, Damaraju and Padgett, L.V. (2005). Block Designs: Analysis, Combinatorics and Applications. World Scientific.
• Street, Anne Penfold and Street, Deborah J. (1987). Combinatorics of Experimental Design. Oxford U. P. [Clarendon]. pp. 400+xiv. ISBN 0198532563.

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