Osceola County, Iowa

Osceola County, Iowa
Osceola County, Iowa
Map of Iowa highlighting Osceola County
Location in the state of Iowa
Map of the U.S. highlighting Iowa
Iowa's location in the U.S.
Founded 1871
Seat Sibley
Area
 - Total
 - Land
 - Water

399.48 sq mi (1,035 km²)
398.77 sq mi (1,033 km²)
0.71 sq mi (2 km²), 0.18%
Population
 - (2010)
 - Density

6,462
16/sq mi (6/km²)
Time zone Central: UTC-6/-5
Website osceolacountyia.org
Footnotes: Population [1]

Osceola County is a county located in the U.S. state of Iowa. It is named for Seminole war chief Osceola. The population was 6,462 in the 2010 census, a decline from 7,003 in the 2000 census. [1][2] The county seat is Sibley, named for H. H. Sibley of Minnesota.[3]

Contents

Geography

According to the 2000 census, the county has a total area of 399.48 square miles (1,034.6 km2), of which 398.77 square miles (1,032.8 km2) (or 99.82%) is land and 0.71 square miles (1.8 km2) (or 0.18%) is water.[4] The highest natural point in Iowa, Hawkeye Point at 1,670 feet (509 m), is located in Osceola County.[5]

Major highways

Adjacent counties

History

Osceola County was formed in 1871. It was named after the eponymous chief of the Seminole. It is the smallest and most recent county in Iowa. In the same year the first settler arrived, Captain Eldred Huff, and laid his claim. On January 1, 1872, the county government conferred for the first time. The first courthouse, constructed of wood, was built in November of the following year and simultaneously served as the conference chamber, school and church. In September 1903, the second courthouse was finished and was wired for electricity in October, 1915.

Demographics

Historical populations
Census Pop.
1880 2,219
1890 5,574 151.2%
1900 8,725 56.5%
1910 8,956 2.6%
1920 10,223 14.1%
1930 10,182 −0.4%
1940 10,607 4.2%
1950 10,181 −4.0%
1960 10,064 −1.1%
1970 8,555 −15.0%
1980 8,371 −2.2%
1990 7,267 −13.2%
2000 7,003 −3.6%
2010 6,462 −7.7%
Iowa Data Center [2]

2010 census

The 2010 census recorded a population of 6,462 in the county, with a population density of 16.2048/sq mi (6.2567/km2). There were 2,990 housing units, of which 2,682 were occupied. [1]

2000 census

2000 Census Age Pyramid for Osceola County

As of the census[6] of 2000, there were 7,003 people, 2,778 households, and 1,941 families residing in the county. The population density was 18 people per square mile (7/km²). There were 3,012 housing units at an average density of 8 per square mile (3/km²). The racial makeup of the county was 98.04% White, 0.11% Black or African American, 0.26% Native American, 0.20% Asian, 0.01% Pacific Islander, 0.84% from other races, and 0.53% from two or more races. 1.78% of the population were Hispanic or Latino of any race.

There were 2,778 households out of which 31.70% had children under the age of 18 living with them, 62.00% were married couples living together, 5.10% had a female householder with no husband present, and 30.10% were non-families. 27.60% of all households were made up of individuals and 15.10% had someone living alone who was 65 years of age or older. The average household size was 2.48 and the average family size was 3.03.

In the county the population was spread out with 26.10% under the age of 18, 7.20% from 18 to 24, 26.20% from 25 to 44, 21.60% from 45 to 64, and 18.90% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 95.00 males. For every 100 females age 18 and over, there were 94.30 males.

The median income for a household in the county was $34,274, and the median income for a family was $41,977. Males had a median income of $29,624 versus $20,522 for females. The per capita income for the county was $16,463. About 6.00% of families and 7.00% of the population were below the poverty line, including 7.90% of those under age 18 and 9.80% of those age 65 or over.

Communities

Cities

Unincorporated communities

  • Allendorf

See also

References

External links

Coordinates: 43°22′40″N 95°37′40″W / 43.37778°N 95.62778°W / 43.37778; -95.62778


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