- Reactions on surfaces
By "reactions on surfaces" it is understood reactions in which at least one of the steps of the
reaction mechanism is theadsorption of one or more reactants. The mechanisms for these reactions, and therate equation s are of extreme importance forheterogeneous catalysis .imple decomposition
If a reaction occurs through these steps:
A + S unicode|⇌ AS → Products
Where A is the reactant and S is an adsorption site on the surface. If the
rate constant s for the adsorption, desorption and reaction are k1, k-1 and k2 then, the global reaction rate is: r=-frac {dC_A}{dt}=k_2 C_{AS}=k_2 heta C_Swhere C_{AS} is the concentration of occupied sites, heta is the surface coverage and C_S is the total number of sites (occupied or not).
C_S is highly related to the total surface area of the adsorbent: the bigger the surface area, the more sites and the faster the reaction. This is the reason why heterogeneous catalysts are usually chosen to have great surface areas (in the order of hundred m2/gram)
If we apply the steady state approximation to AS, then
frac {dC_{AS{dt}= 0 = k_1 C_A C_S (1- heta)- k_2 heta C_S -k_{-1} heta C_S so heta =frac {k_1 C_A}{k_1 C_A + k_{-1}+k_2} and r=-frac {dC_A}{dt}= frac {k_1 k_2 C_A C_S}{k_1 C_A + k_{-1}+k_2}. Please notice that, with K_1=frac{k_1}{k_{-1, the formula was divided by k_{-1}.
The result is completely equivalent to the
Michaelis-Menten kinetics . The rate equation is complex, and the reaction order is not clear. In experimental work, usually two extreme cases are looked for in order to prove the mechanism. In them, therate-determining step can be:*Limiting step: Adsorption/Desorptionk_2 >> k_1C_A, k_{-1}, so r approx k_1 C_A C_S.The order respect to A is 1. Examples of this mechanism are N2O on gold and HI on
platinum *Limiting Step: Reactionk_2 << k_1C_A, k_{-1} so heta =frac {k_1 C_A}{k_1 C_A + k_{-1 which is just Langmuir isotherm and r= frac {K_1 k_2 C_A C_S}{K_1 C_A+1}. Depending on the concentration of the reactant the rate changes::* Low concentrations, then r= K_1 k_2 C_A C_S, that is to say a first order reaction.:* High concentration, then r= k_2 C_S. It is a zeroth order reaction.
Bimolecular reaction
Langmuir -Hinshelwood mechanismThis mechanism proposes that both molecules adsorb and the adsorbed molecules undergo a bimolecular reaction:
A + S unicode|⇌ AS
B + S unicode|⇌ BS
AS + BS → Products
The rate constants are now k_1,k_{-1},k_2,k_{-2} and k for adsorption of A, adsorption of B, and reaction. The rate law is: r=k heta_A heta_B C_S^2
Proceeding as before we get heta_A=frac{k_1C_A heta_E}{k_{-1}+kC_S heta_B}, where heta_E is the fraction of empty sites, so heta_A+ heta_B+ heta_E=1. Let us assume now that the rate limiting step is the reaction of the adsorbed molecules, which is easily understood: the probability of two adsorbed molecules colliding is low.Then heta_A=K_1C_A heta_E, with K_i=k_i/k_{-1}, which is nothing but Langmuir isotherm for two adsorbed gases, with adsorption constants K_1 and K_2.Calculating heta_E from heta_A and heta_B we finally get::r=k C_S^2 frac{K_1K_2C_AC_B}{(1+K_1C_A+K_2C_B)^2}.
The rate law is complex and there is no clear order respect to any of the reactants but we can consider different values of the constants, for which it is easy to measure integer orders:
*Both molecules have low adsorptionThat means that 1 >> K_1C_A, K_2C_B, so r=C_S^2 K_1K_2C_AC_B. The order is one respect to both the reactants
*One molecule has very low adsorptionIn this case K_1C_A, 1>>K_2C_B, so r=C_S^2 frac{K_1K_2C_AC_B}{(1+K_1C_A)^2}. The reaction order is 1 respect to B. There are two extreme possibilities now::# At low concentrations of A, r=C_S^2 K_1K_2C_AC_B, and the order is one respect to A.:# At high concentrations, r=C_S^2 frac{K_2C_B}{K_1C_A}. The order es minus one respect to A. The higher the concentration of A, the slower the reaction goes, in this case we say that A inhibits the reaction.
*One molecule has very high adsorptionOne of the reactants has very high adsorption and the other one doesn't adsorb strongly.
K_1C_A >> 1, K_2C_B, so r=C_S^2 frac{K_2C_B}{K_1C_A}. The reaction order is 1 respect to B and -1 respect to A. Reactant A inhibits the reaction at all concentrations.
The following reactions follow a Langmuir-Hinshelwood mechanism [http://www.theochem.uni-duisburg.de/DC/material/exarbeiten/Exarbeit-Alex/a_7.htm] :
* 2 CO + O2 → 2 CO2 on aplatinum catalyst.
* CO + 2H2 → CH3OH on aZnO catalyst.
* C2H4 + H2 → C2H6 on acopper catalyst.
* N2O + H2 → N2 + H2O on a platinum catalyst.
* C2H4 + ½ O2 → CH3CHO on apalladium catalyst.
* CO + OH → CO2 + H+ + e- on a platinum catalyst.Eley-Rideal mechanism
This mechanism proposes that only one of the molecules adsorbs and the other one reacts with it directly, without adsorbing:
A + S unicode|⇌ AS
AS + B → Products
Constants are k_1, k_{-1} and k and rate equation is r = k C_S heta_A C_A C_B. Applying steady state approximation to AS and proceeding as before (considering the reaction the limiting step once more) we get r=C_S C_Bfrac{K_1C_A}{K_1C_A+1}. The order is one respect to B. There are two possibilities, depending on the concetration of reactant A:
:* At low concentrations of A, r=C_S K_1K_2C_AC_B, and the order is one with respect to A.
:* At high concentrations of A, r=C_S K_2C_B, and the order is zero with respect to A.
The following reactions follow a Eley-Rideal mechanism [http://www.theochem.uni-duisburg.de/DC/material/exarbeiten/Exarbeit-Alex/a_7.htm] :
* C2H4 + ½ O2 (adsorbed) → H2COCH2 The dissociative adsorption of oxygen is also possible, which leads to secondary products carbondioxide andwater .
* CO2 + H2(ads.) → H2O + CO
* 2NH3 + 1½ O2 (ads.) → N2 + 3H2O on a platinum catalyst
* C2H2 + H2 (ads.) → C2H4 onnickel oriron catalystsReferences
[http://www.chem.ucl.ac.uk/cosmicdust/er-lh.htm Graphic models of Eley Rideal and Langmuir Hinshelwood mechanisms]
[http://www.theochem.uni-duisburg.de/DC/material/exarbeiten/Exarbeit-Alex/a_7.htm German page with mechanisms, rate equation graphics and references]
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