- Equations for a falling body
Under normal earth-bound conditions, when objects move owing to a constant

gravitation alforce a set of**dynamical equations**describe the resultanttrajectories . For example,Newton's law of universal gravitation simplifies to "F" = "mg", where m is the mass of the body. This assumption is reasonable for objects falling to earth over the relatively short vertical distances of our everyday experience, but is very much untrue over larger distances, such as spacecraft trajectories.Please note that in this article any resistance from air (drag) is neglected.**History**Galileo was the first to demonstrate and then formulate these equations. He used a

ramp to study rolling balls, the ramp slowing the acceleration enough to measure the time taken for the ball to roll a known distance. He measured elapsed time with awater clock , using an "extremely accurate balance" to measure the amount of waterfn|2.The equations ignore air resistance, which has a dramatic effect on objects falling an appreciable distance in air, causing them to quickly approach a

terminal velocity . For example, a person jumping headfirst from an airplane will never exceed a speed of about 200 KPH, app 124MPH , due to air resistance. The effect of air resistance varies enormously depending on the size and geometry of the falling object – for example, the equations are hopelessly wrong for a feather, which has a low mass but offers a large resistance to the air. (In the absence of an atmosphere all objects fall at the same rate, as astronautDavid Scott demonstrated by dropping a hammer and a feather on the surface of theMoon .)The equations also ignore the rotation of the Earth, failing to describe the

Coriolis effect for example. Nevertheless, they are usually accurate enough for dense and compact objects falling over heights not exceeding the tallest man-made structures.**Overview**Near the surface of the Earth, use

**"g" = 9.8 m/s²**(metres per second squared; which might be thought of as "metres per second, per second", or 32 ft/s² as "feet per second per second"), approximately. For other planets, multiply "g" by the appropriate scaling factor. It is essential to use a coherent set of units for "g", "d", "t" and "v". Assuming SI units, "g" is measured in metres per second squared, so "d" must be measured in metres, "t" in seconds and "v" in metres per second. In all cases the body is assumed to start from rest, and air resistance is neglected, or in other words, they assume constant acceleration. Generally, in Earth's atmosphere, this means all results below will be quite inaccurate after only 5 seconds of fall, after which an object's velocity will be 49 m/s (9.8 m/s² × 5 s). On an airless body like the moon or relatively airless body like Mars, with appropriate changes in g, these equations will yield accurate results over much longer times and much higher velocities.**Example:**the first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 1^{2}= 4.9 meters. After two seconds it will have fallen 1/2 × 9.8 × 2^{2}= 19.6 metres; and so on.**NOTE for other astronomical bodies**: For astronomical bodies other than Earth, and for short distances of fall at other than "ground" level,**g**in the above equations may be replaced by**GM/r²**where**G**is thegravitational constant ,**M**is the mass of the astronomical body, and**r**is the radius from the falling object to the center of the body. Values obtained are correct only in cases where the distance of fall**d**is small compared with**r**.**Gravitational potential**For any mass distribution there is a

scalar field , the gravitationalpotential (ascalar potential ), which is the gravitational potential energy per unit mass of a point mass, as function of position. It is$-\; G\; int\{1\; over\; r\}\; dm$

where the integral is taken over all mass.Minus its

gradient is the gravity field itself, and minus its Laplacian is thedivergence of the gravity field, which is everywhere equal to -4π"G" times the local density.Thus when outside masses the potential satisfies

Laplace's equation (i.e., the potential is aharmonic function ), and when inside masses the potential satisfiesPoisson's equation with, as right-hand side, 4π"G" times the local density.**Acceleration relative to the rotating Earth**The acceleration measured on the rotating surface of the Earth is not quite the same as the acceleration that is measured for a free-falling body because of the

centrifugal force . In other words, the apparent acceleration in the rotating frame of reference is the total gravity vector minus a small vector toward the north-south axis of the Earth, corresponding to staying stationary in that frame of reference.**Notes*** See the works of

Stillman Drake , for a comprehensive study of Galileo and his times, theScientific Revolution .**See also***

Gravitation **External links*** [

*http://www.gravitycalc.com Falling body equations calculator*]

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