- Belt problem
The

**belt problem**is the problem of finding the length of a crossed belt that connects two circular pulleys with radius "r"_{1}and "r"_{2}whose centres are separated by a distance "P" (see diagram below). The solution of the belt problem requirestrigonometry and the concepts of the bitangent line, thevertical angle , andcongruent angles .**olution**Clearly triangles ACO and ADO are congruent

right angled triangle s, as are triangles BEO and BFO. In addition, triangles ACO and BEO are similar. Therefore angles CAO, DAO, EBO and FBO are all equal. Denoting this angle by φ, the length of the belt is:CO + DO + EO + FO + arc CD + arc EF

:$=2r\_1\; an(varphi)\; +\; 2r\_2\; an(varphi)\; +\; (2pi-2varphi)r\_1\; +\; (2pi-2varphi)r\_2$

:$=2(r\_1+r\_2)(\; an(varphi)\; +\; pi-\; varphi).$

To find φ we see from the similarity of triangles ACO and BEO that

:$frac\{AO\}\{BO\}=frac\{AC\}\{BE\}$

:$Rightarrow\; frac\{P-x\}\{x\}\; =\; frac\{r\_1\}\{r\_2\}$

:$Rightarrow\; frac\{P\}\{x\}\; =\; frac\{r\_1+r\_2\}\{r\_2\}$

:$Rightarrow\; cos(varphi)\; =\; frac\{r\_2\}\{x\}\; =\; frac\{r\_1+r\_2\}\{P\}$

:$Rightarrow\; varphi=cos^\{-1\}left(frac\{r\_1+r\_2\}\{P\}\; ight).$

For fixed "P" the length of the belt depends only on the sum of the radius values "r"

_{1}+ "r"_{2}, and not on their individual values.**Pulley problem**There are other types of problems similar to the belt problem. The pulley problem, as shown above, is similar to the belt problem, except that the belt does not cross itself. In the pulley problem the length of the belt is

:$2Psin(varphi)+2(r\_1+r\_2)(pi-varphi),$

where

:$varphi=cos^\{-1\}left(frac\{r\_1-r\_2\}\{P\}\; ight).$

**Applications**The belt problem is used in real life in the design of aeroplanes, bicycle gears, cars, and other items with pulleys or belts that cross each other as in the belt problem. The pulley problem is used in the design of airport luggage belts and automated factory lines.

**See also***

Tangent lines to circles

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