- Root mean square
In

mathematics , the**root mean square**(abbreviated**RMS**or**rms**), also known as the**quadratic mean**, is a statistical measure of the magnitude of a varying quantity. It is especially useful when variates are positive and negative, e.g., sinusoids.It can be calculated for a series of discrete values or for a continuously varying function. The name comes from the fact that it is the

square root of the mean of the squares of the values. It is a special case of the power mean with the exponent "p" = 2.**Definition**$x\_\; ext\{rms\}\; =\; sqrt\{\; langle\; x\_1^2\; +\; x\_2^2\; +\; x\_3^2\; +...+\; x\_N^2\; angle/N\}\; ,!$

**Ways of calculating the root mean square**The RMS of a collection of $n$ values $\{x\_1,x\_2,dots,x\_n\}$ is

:$x\_\{mathrm\{rms\; =\; sqrt$1 over n} sum_{i=1}^{n} x_i^2} =sqrt x_1^2 + x_2^2 + cdots + x_n^2} over n}

The corresponding formula for a continuous function $f(t)$ defined over the interval $T\_1\; le\; t\; le\; T\_2$ is

:$f\_\{mathrm\{rms$ = sqrt 1 over {T_2-T_1 {int_{T_1}^{T_2} { [f(t)] }^2, dt

The RMS of a periodic function is equal to the RMS of one period of the function. The RMS value of a continuous function or signal can be approximated by taking the RMS of a series of equally spaced samples. Additionally, the RMS value of various waveforms can also be determined without calculus, as shown by Cartwright [

*citation*] .

last=Cartwright

first=Kenneth V

title=Determining the Effective or RMS Voltage of Various Waveforms without Calculus

journal=Technology Interface

volume=8

issue=1

pages=20 pages

date=Fall 2007

year=2007

url=http://technologyinterface.nmsu.edu/Fall07/**Uses**The RMS value of a function is often used in

physics andelectrical engineering .**Average electrical power**Engineers often need to know the power, $P$, dissipated by an electrical resistance, $R$. It is easy to do the calculation when there is a constant current, $I$, through the resistance. For a load of R ohms, power is defined simply as:

:$P\; =\; I^2\; R.,!$

However, if the current is a time-varying function, $I(t)$, this formula must be extended to reflect the fact that the current (and thus the instantaneous power) is varying over time. If the function is periodic (such as household AC power), it is nonetheless still meaningful to talk about the "average" power dissipated over time, which we calculate by taking the simple average of the power at each instant in the waveform or, equivalently, the squared current. That is,:So, the RMS value, $I\_mathrm\{RMS\}$, of the function $I(t)$ is the constant signal that yields the same average power dissipation.

We can also show by the same method that for a time-varying

voltage , $V(t)$, with RMS value $V\_mathrm\{RMS\}$,:$P\_mathrm\{avg\}\; =\; \{(V\_mathrm\{RMS\})^2over\; R\}.,!$

This equation can be used for any periodic

waveform , such as a sinusoidal orsawtooth wave form, allowing us to calculate the mean power delivered into a specified load.By taking the square root of both these equations and multiplying them together, we get the equation

:$P\_mathrm\{avg\}\; =\; V\_mathrm\{RMS\}I\_mathrm\{RMS\}.,!$

Both derivations depend on "voltage and current being proportional" (i.e., the load, "R", is purely resistive). Reactive loads (i.e., loads capable of not just dissipating energy but also storing it) are discussed under the topic of

AC power .In the common case of

alternating current when $I(t)$ is a sinusoidal current, as is approximately true for mains power, the RMS value is easy to calculate from the continuous case equation above. If we define $I\_\{mathrm\{p$ to be the amplitude of the current, then::$I\_\{mathrm\{RMS\; =\; sqrt$1 over {T_2-T_1 {int_{T_1}^{T_2} {(I_mathrm{p}sin(omega t)}, })^2 dt}.,!

where "t" is time and "ω" is the

angular frequency ("ω" = 2π/"T", where"T" is the period of the wave).Since $I\_\{mathrm\{p$ is a positive constant:

:$I\_\{mathrm\{RMS\; =\; I\_mathrm\{p\}sqrt$1 over {T_2-T_1 {int_{T_1}^{T_2} {sin^2(omega t)}, dt.

Using a trigonomentric identity to eliminate squaring of trig function:

:$I\_\{mathrm\{RMS\; =\; I\_mathrm\{p\}sqrt$1 over {T_2-T_1 {int_{T_1}^{T_2} 1 - cos(2omega t) over 2, dt

:$I\_\{mathrm\{RMS\; =\; I\_mathrm\{p\}sqrt$1 over {T_2-T_1 left [ t over 2} -{ sin(2omega t) over 4omega ight ] _{T_1}^{T_2} }

but since the interval is a whole number of complete cycles (per definition of RMS), the $sin$ terms will cancel, leaving:

:$I\_\{mathrm\{RMS\; =\; I\_mathrm\{p\}sqrt$1 over {T_2-T_1 left [ t over 2 ight ] _{T_1}^{T_2} } = I_mathrm{p}sqrt 1 over {T_2-T_1 {T_2-T_1} over 2 } = {I_mathrm{p} over {sqrt 2.

A similar analysis leads to the analogous equation for voltage:

:$V\_\{mathrm\{RMS\; =\; \{V\_mathrm\{p\}\; over\; \{sqrt\; 2.$

Because of their usefulness in carrying out power calculations, listed

voltage s for power outlets, e.g. 120 V (USA) or 230 V (Europe), are almost always quoted in RMS values, and not peak values. Peak values can be calculated from RMS values from the above formula, which implies "V"_{"p"}= "V"_{RMS}× √2, assuming the source is a pure sine wave. Thus the peak value of the mains voltage in the USA is about 120 × √2, or about 170 volts. The peak-to-peak voltage, being twice this, is about 340 volts. A similar calculation indicates that the peak-to-peak mains voltage in Europe is about 650 volts.It is also possible to calculate the RMS power of a signal. By analogy with RMS voltage and RMS current, RMS power is the square root of the mean of the square of the power over some specified time period. This quantity, which would be expressed in units of watts (RMS), has no physical significance. However, the term "RMS power" is sometimes used in the audio industry as a synonym for "mean power" or "average power". For a discussion of audio power measurements and their shortcomings, see

Audio power .**Amplifier power efficiency**The

electrical efficiency of anelectronic amplifier is the ratio of mean output power to mean input power. As discussed, if the output is resistive, the mean output power can be found using the RMS values of output current and voltage signals. However, the mean value of the current should be used to calculate the input power. That is, the power delivered by the amplifier supplied by constantvoltage $V\_\{CC\}$ is :$P\_mathrm\{input\}(t)\; =\; I\_Q\; V\_\{CC\}\; +\; I\_mathrm\{out\}(t)\; V\_\{CC\},$where $I\_Q$ is the amplifier's operating current. Clearly, because $V\_\{CC\}$ is constant, the time average of $P\_mathrm\{input\}$ depends on the time "average" value of $I\_mathrm\{out\}$ and not its RMS value. That is,:$langle\; P\_mathrm\{input\}(t)\; angle\; =\; I\_Q\; V\_\{CC\}\; +\; langle\; I\_mathrm\{out\}(t)\; angle\; V\_\{CC\},$**Root mean square velocity**In

physics , the**root mean square velocity**is defined as the square root of the average velocity-squared of the molecules in agas . The RMS velocity of an ideal gas is calculated using the following equation::$\{v\_mathrm\{RMS\; =\; \{sqrt\{3RT\; over\; \{M\}$

where $R$ represents the

ideal gas constant (in this case, 8.314 J/(mol⋅K)), $T$ is the temperature of the gas inkelvin s, and $M$ is themolar mass of the compound in kilograms per mole. Note that the unit of mass is in kilograms per mole because the joule is given in kilogram meters squared per second squared.**Relationship to the arithmetic mean and the standard deviation**If $ar\{x\}$ is the

arithmetic mean and $sigma\_\{x\}$ is thestandard deviation of a population (the equation is different when $sigma\_\{x\}$ is for a sample) then: :$x\_\{mathrm\{rms^2\; =\; ar\{x\}^2\; +\; sigma\_\{x\}^2.$From this it is clear that the RMS value is always greater than or equal to the average, in that the RMS includes the "error" / square deviation as well.

Physical scientists often use the term "root mean square" as a synonym for

standard deviation when referring to the square root of the mean squared deviation of a signal from a given baseline or fit. This is useful for electrical engineers in calculating the "AC only" RMS of a signal. Standard deviation being the root mean square of a signal's variation about the mean, rather than about 0, the DC component is removed (i.e. RMS(signal) = Stdev(signal) if the mean signal is 0).**ee also***

Generalized mean

*L2 norm

*Least squares

*Root mean square speed

*Root mean square deviation (or error)

*Table of mathematical symbols **References****External links*** [

*http://www.easycalculation.com/statistics/root-mean-square.php RMS calculator*]

* [*http://www.hifi-writer.com/he/misc/rmspower.htm A case for why RMS is a misnomer when applied to audio power*]

* [*http://www.opamp-electronics.com/tutorials/measurements_of_ac_magnitude_2_01_03.htm RMS, Peak and Average for some waveforms*]

* [*http://phy.hk/wiki/englishhtm/Rms.htm A Java applet on learning RMS*]

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