Apollonius' theorem

Apollonius' theorem

In elementary geometry, Apollonius' theorem is a theorem relating several elements in a triangle.

It states that given a triangle "ABC", if "D" is any point on "BC" such that it divides "BC" in the ratio "n":"m" (or mBD = nDC), then

:mAB^2 + nAC^2 = mBD^2 + nDC^2 + (m+n)AD^2.

Special cases of the theorem

* When m = n (=1), that is, "AD" is the median falling on "BC", the theorem reduces to

::AB^2 + AC^2 = BD^2 + DC^2 + 2AD^2. ,

* When in addition "AB" = "AC", that is, the triangle is isosceles, the theorem reduces to the Pythagorean theorem,

:: AD^2 + BD^2 = AB^2 (= AC^2).,

In simpler words, in any triangle ABC,, if AD, is a median, then AB^2 + AC^2 = 2(AD^2+BD^2),!

To prove this theorem, let AX,' be a perpendicular dropped on BC, from the point "'A,. Then, in the right-angled triangles ABX, and ACX,, by Pythagoras' theorem, we have

: AB^2 = AX^2 + BX^2,

: = AX^2 + (BD+DX)^2,

: = AX^2 + BD^2 + DX^2 + 2.BD.DXqquad (i)

and

: AC^2 = AX^2 + CX^2,

: = AX^2 + (CD-DX)^2,

: = AX^2 + CD^2 + DX^2 - 2.CD.DX.qquad (ii)

Adding equations ("i") and ("ii"),

: AB^2 + AC^2,!

: = AX^2 + BD^2 + DX^2 + 2.BD.DX + AX^2 + CD^2 + DX^2 - 2.CD.DX,!

: = 2(AX^2 + DX^2 + BD^2),

since BD=DC,,

: 2.BD.DX=2.DC.DX,!

: = 2(AX^2 + DX^2) + 2BD^2,!

: = 2(AD^2 + BD^2),!

since AXD, is a right angle"

And thus the theorem is proved.

ee also

* Stewart's theorem
* Parallelogram law
* Pythagorean theorem
* Menelaus' theorem
* Ceva's theorem


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