- Sierpiński space
In
mathematics , Sierpiński space (or the connected two-point set) is afinite topological space with two points, only one of which is closed.It is the smallest example of atopological space which is neither trivial nor discrete. It is named afterWacław Sierpiński .The Sierpiński space has important relations to the theory of computation and
semantics . [An online paper, it explains the motivation, why the notion of “topology” can be applied in the investigation of concepts of the computer science. Alex Simpson: [http://www.dcs.ed.ac.uk/home/als/Teaching/MSfS/ Mathematical Structures for Semantics] . Chapter III: [http://www.dcs.ed.ac.uk/home/als/Teaching/MSfS/l3.ps Topological Spaces from a Computational Perspective] . The “References” section provides many online materials ondomain theory .]Definition and fundamental properties
Explicitly, the Sierpiński space is a
topological space "S" whose underlying point set is {0,1} and whoseopen set s are:Theclosed set s are:So thesingleton set {0} is closed (but not open) and the set {1} is open (but not closed).The closure operator on "S" is determined by:
A finite topological space is also uniquely determined by its
specialization preorder . For the Sierpiński space thispreorder is actually apartial order and given by:Topological properties
The Sierpiński space "S" is a special case of both the finite
particular point topology (with particular point 1) and the finiteexcluded point topology (with excluded point 0). Therefore "S" has many properties in common with one or both of these families.eparation
*The points 0 and 1 are
topologically distinguishable in "S" since {1} is an open set which contains only one of these points. Therefore "S" is a Kolmogorov (T0) space.
*However, "S" is not T1 since the point 1 is not closed. It follows that "S" is not Hausdorff, or T"n" for any "n" ≥ 1.
*"S" is not regular (orcompletely regular ) since the point 1 and the disjoint closed set {0} cannot be separated by neighborhoods. (Also regularity in the presence of T0 would imply Hausdorff).
*"S" is vacuously normal and completely normal since there are no nonemptyseparated set s.
*"S" is not perfectly normal since the disjoint closed sets ∅ and {0} cannot be precisely separated by a function. Indeed {0} cannot be thezero set of any continuous function "S" → R since every such function is constant.Connectedness
*The Sierpiński space "S" is both
hyperconnected (since every nonempty open set contains 1) andultraconnected (since every nonempty closed set contains 0).
*It follows that "S" is both connected and path connected.
*A path from 0 to 1 in "S" is given by the function: "f"(0) = 0 and "f"("t") = 1 for "t" > 0. The function "f" : "I" → "S" is continuous since "f"−1(1) = (0,1] which is open in "I".
*Like all finite topological spaces, "S" islocally path connected .
*The Sierpiński space is contractible, so thefundamental group of "S" is trivial (as are all thehigher homotopy groups ).Compactness
*Like all finite topological spaces, the Sierpiński space is both compact and
second-countable .
*The compact subset {1} of "S" is not closed showing that compact subsets of T0 spaces need not be closed.
*Everyopen cover of "S" must contain "S" itself since "S" is the only open neighborhood of 0. Therefore every open cover of "S" has at opensubcover consisting of a single set: {"S"}.
*It follows that "S" is fully normal. [Steen and Seebach incorrectly list the Sierpiński space as "not" being fully normal (or fully T4 in their terminology).]Convergence
*Every
sequence in "S" converges to the point 0. This is because the only neighborhood of 0 is "S" itself.
*A sequence in "S" converges to 1 if and only if the sequence contains only finitely many terms equal to 0 (i.e. the sequence is eventually just 1's).
*The point 1 is acluster point of a sequence in "S" if and only if the sequence contains infinitely many 1's.
*"Examples":
**1 is not a cluster point of (0,0,0,0,…).
**1 is a cluster point (but not a limit) of (0,1,0,1,0,1,…).
**The sequence (1,1,1,1,…) converges to both 0 and 1.Metrizability
*The Sierpiński space "S" is not metrizable or even pseudometrizable since it is not regular.
* "S" is generated by thehemimetric (or pseudo-quasimetric ) and .Other properties
*There are only three continuous maps from "S" to itself: the
identity map and theconstant map s to 0 and 1.
*It follows that thehomeomorphism group of "S" is trivial.Continuous functions to the Sierpiński space
Let "X" be an arbitrary set. The set of all functions from "X" to the set {0,1} is typically denoted 2"X". These functions are precisely the characteristic functions of "X". Each such function is of the form:where "U" is a
subset of "X". In other words, the set of functions 2"X" is inbijective correspondence with "P"("X"), thepower set of "X". Every subset "U" of "X" has its characteristic function χ"U" and every function from "X" to {0,1} is of this form.Now suppose "X" is a topological space and let {0,1} have the Sierpiński topology. Then a function χ"U" : "X" → "S" is continuous if and only if χ"U"−1(1) is open in "X". But, by definition:So χ"U" is continuous if and only if "U" is open in "X". Let C("X","S") denote the set of all continuous maps from "X" to "S" and let "T"("X") denote the topology of "X" (i.e. the family of all open sets). Then we have a bijection from "T"("X") to C("X","S") which sends the open set "U" to χ"U".:That is, if we identify 2"X" with "P"("X"), the subset of continuous maps C("X","S") ⊂ 2"X" is precisely the topology of "X": "T"("X") ⊂ "P"("X").
Categorical description
The above construction can be described nicely using the language of
category theory . There iscontravariant functor "T" : Top → Set from thecategory of topological spaces to thecategory of sets which assigns each topological space "X" its set of open sets "T"("X") and each continuous function "f" : "X" → "Y" thepreimage
The statement then becomes: the functor "T" is represented by ("S", {1}) where "S" is the Sierpiński space. That is, "T" isnaturally isomorphic to theHom functor Hom(–, "S") with the natural isomorphism determined by theuniversal element {1} ∈ "T"("S").The initial topology
Any topological space "X" has the
initial topology induced by the family C("X","S") of continuous functions to Sierpiński space. Indeed, in order to coarsen the topology on "X" one must remove open sets. But removing the open set "U" would render χ"U" discontinuous. So "X" has the coarsest topology for which each function in C("X","S") is continuous.The family of functions C("X","S") separates points in "X" if and only if "X" is a T0 space. Two points "x" and "y" will be separated by the function χ"U" if and only if the open set "U" contains precisely one of the two points. This is exactly what it means for "x" and "y" to be
topologically distinguishable .Therefore if "X" is T0, we can embed "X" as a subspace of a product of Sierpiński spaces, where there is one copy of "S" for each open set "U" in "X". The embedding
is given by:Since subspaces and products of T0 spaces are T0, it follows that a topological space is T0 if and only if it ishomeomorphic to a subspace of a power of "S".In algebraic geometry
In
algebraic geometry the Sierpiński space arises as the spectrum, Spec("R"), of adiscrete valuation ring "R" such as Z(2) (the localization of theinteger s at theprime ideal generated by 2). Thegeneric point of Spec("R"), coming from thezero ideal , corresponds to the open point 1, while thespecial point of Spec("R"), coming from the uniquemaximal ideal , corresponds to the closed point 0.ee also
*
Finite topological space
*Pseudocircle Notes
References
*Citation | last1=Steen | first1=Lynn Arthur | author1-link=Lynn Arthur Steen | last2=Seebach | first2=J. Arthur Jr. | author2-link=J. Arthur Seebach, Jr. | title=
Counterexamples in Topology | origyear=1978 | publisher=Springer-Verlag | location=Berlin, New York | edition=Dover reprint of 1978 | isbn=978-0-486-68735-3 | id=MathSciNet|id=507446 | year=1995
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