- Hahn–Banach theorem
In
mathematics , the Hahn–Banach theorem is a central tool infunctional analysis . It allows the extension ofbounded linear operator s defined on a subspace of somevector space to the whole space, and it also shows that there are "enough" continuous linear functionals defined on everynormed vector space to make the study of thedual space interesting. It is named forHans Hahn andStefan Banach who proved this theorem independently in the 1920s.Formulation
The most general formulation of the theorem needs some preparation. Given a
vector space over the scalar field (either thereal number s or thecomplex number s ), a function is called "sublinear" if:
As it can be easily proven, every norm and every
seminorm on is sublinear. Other sublinear functions can be useful as well.The Hahn–Banach theorem states that if is a sublinear function, and is a
linear functional on a subspace of which is dominated by on i.e.:
then there exists a linear extension of "φ" to the whole space i.e. there exists
linear functional "ψ" such that:
and
:
The extension "ψ" is in general not uniquely specified by "φ" and the proof gives no method as to how to find "ψ": in the case of an infinite dimensional space , it depends on
Zorn's lemma , one formulation of theaxiom of choice .It is possible to relax slightly the sublinearity condition on , requiring only that
:
according to (Reed and Simon, 1980). This reveals the intimate connection between the Hahn–Banach theorem and
convexity .The Mizar project has completely formalized and automatically checked the proof of the Hahn–Banach theorem in the [http://mizar.uwb.edu.pl/JFM/Vol5/hahnban.html HAHNBAN file] .
Important consequences
The theorem has several important consequences, some of are which also sometimes called "Hahn–Banach theorem":
* If "V" is a normed vector space with subspace "U" (not necessarily closed) and if φ : "U" → K is continuous and linear, then there exists an extension ψ : "V" → K of φ which is also continuous and linear and which has the same norm as φ (seeBanach space for a discussion of the norm of a linear map). In other words, in the category of normed vector spaces, the space "K" is aninjective object .
* If "V" is a normed vector space with subspace "U" (not necessarily closed) and if "z" is an element of "V" not in the closure of "U", then there exists a continuous linear map ψ : "V" → K with ψ("x") = 0 for all "x" in "U", ψ("z") = 1, and ||ψ|| = 1/dist("z","U").Hahn-Banach separation theorem
Another version of Hahn-Banach theorem is known as Hahn-Banach separation theorem. [ Klaus Thomsen, [http://www.imf.au.dk/kurser/advanalyse/F06/lecture6pr.pdf The Hahn-Banach separation theorem] , Aarhus University, [http://www.imf.au.dk/kurser/advanalyse/F06/ Advanced Analysis lecture notes] ] [Gabriel Nagy, [http://www.math.ksu.edu/~nagy/real-an/ap-e-h-b.pdf Real Analysis] [http://www.math.ksu.edu/~nagy/real-an/ lecture notes] ] It has numerous uses in
convex geometry . [R. Harvey and H. B. Lawson, "An intrinsic characterisation of Kahler manifolds," Invent. Math 74 (1983) 169-198.]Theorem: Let be a
topological vector space over ,and "", "" convex, non-empty subsets of "".Assume that .Then(i) If "" is open,then there exists a continuous linear map and such that for all ,
(ii) If "" is locally convex,"" is compact,and "" closed,then there exists a continuous linear map and such that for all , .
Relation to the axiom of choice
As mentioned earlier, the
axiom of choice implies the Hahn–Banach theorem. The converse is not true. One way to see that is by noting that theultrafilter lemma , which is strictly weaker than the axiom of choice, can be used to show the Hahn–Banach theorem, although the converse is not the case. The Hahn–Banach theorem can in fact be proved using even weaker hypotheses than the ultrafilter lemma. [D. Pincus, "The strength of Hahn–Banach's Theorem", in: Victoria Symposium on Non-standard Analysis, Lecture notes in Math. 369, Springer 1974, pp. 203-248. Citation from M. Foreman and F. Wehrung, [http://matwbn.icm.edu.pl/ksiazki/fm/fm138/fm13812.pdf "The Hahn-Banach theorem implies the existence of a non-Lebesgue measurable set"] , "Fundamenta Mathematicae" 138 (1991), p. 13-19.] For separableBanach space s, Brown and Simpson proved that the Hahn–Banach theorem follows from WKL0, a weak subsystem ofsecond-order arithmetic . [D. K. Brown and S. G. Simpson, "Which set existence axioms are needed to prove the separable Hahn-Banach theorem?", Annals of Pure and Applied Logic, 31, 1986, pp. 123-144. [http://www.math.psu.edu/simpson/papers/hilbert/node7.html#3 Source of citation] .]See also
*
M. Riesz extension theorem References
* Lawrence Narici and Edward Beckenstein, " [http://at.yorku.ca/p/a/a/a/16.htm The Hahn–Banach Theorem: The Life and Times] ", "Topology and its Applications", Volume 77, Issue 2 (1997) Pages 193-211.
* Michael Reed and Barry Simon, "Methods of Modern Mathematical Physics, Vol. 1, Functional Analysis," Section III.3. Academic Press, San Diego, 1980. ISBN 0-12-585050-6.
Notes
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