- Pollard's rho algorithm for logarithms
Pollard's rho algorithm for logarithms is an algorithm for solving the
discrete logarithm problem analogous toPollard's rho algorithm for solving theInteger factorization problem.The goal is to compute such that , where belongs to the group generated by . The algorithm computes integers , , , and such that . Assuming, for simplicity, that the underlying group is cyclic of order and that , we can calculate as a solution of the equation .
To find the needed , , , and the algorithm uses
Floyd's cycle-finding algorithm to find a cycle in the sequence , where the function is assumed to be random-looking and thus is likely to enter into a loop after approximately steps. One way to define such a function is to use the following rules: Divide into three subsets (not necessarilysubgroup s) of approximately equal size: , , and . If is in then double both and ; if then increment , if then increment .Algorithm
Let be a cyclic group of prime order , and given , and a partition , let be a map
and define maps and by
:Inputs "a" a generator of "G", "b" an element of "G":Output An integer "x" such that "ax = b", or failure:# Initialise "a0" ← 0:#::"b0" ← 0:#::"x0" ← 1 ∈ "G":#::"i" ← 1:# "xi" ← "f(xi-1)", "ai" ← "g(xi-1,ai-1)", "bi" ← "h(xi-1,bi-1)":#"x2i" ← "f(f(x2i-2))", "a2i" ← "g(f(x2i-2),g(x2i-2,a2i-2))", "b2i" ← "h(f(x2i-2),h(x2i-2,b2i-2))":# If "xi" = "x2i" then:## "r" ← "bi" - "b2i":## If r = 0 return failure:## x ← "r-1"("a2i" - "ai") mod "p":## return x:# If "xi" ≠ "x2i" then "i" ← "i+1", and go to step 2.
Example
Consider, for example, the group generated by 2 modulo (the order of the group is , 2generates the group of units modulo 1019). The algorithm is implemented by the following C program:
The results are as follows (edited):
i x a b X A B ------------------------------ 1 2 1 0 10 1 1 2 10 1 1 100 2 2 3 20 2 1 1000 3 3 4 100 2 2 425 8 6 5 200 3 2 436 16 14 6 1000 3 3 284 17 15 7 981 4 3 986 17 17 8 425 8 6 194 17 19 .............................. 48 224 680 376 86 299 412 49 101 680 377 860 300 413 50 505 680 378 101 300 415 51 1010 681 378 1010 301 416
That is and so , for which is a solution as expected. As is not prime, there is another solution , for which holds.
Complexity
The running time is approximately O() for a number "n".
References
* J. Pollard, "Monte Carlo methods for index computation mod p", Mathematics of Computation, Volume 32, 1978.
* Alfred J. Menezes, Paul C. van Oorschot, and Scott A. Vanstone, [http://www.cacr.math.uwaterloo.ca/hac/about/chap3.pdf Handbook of Applied Cryptography, Chapter 3] , 2001.
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