- Adjoint endomorphism
In
mathematics , the adjoint endomorphism or adjoint action is anendomorphism ofLie algebra s that plays a fundamental role in the development of the theory ofLie algebras andLie groups .Given an element "x" of a Lie algebra mathfrak{g}, one defines the adjoint action of "x" on mathfrak{g} as the endomorphism extrm{ad}_x :mathfrak{g} o mathfrak{g} with
:extrm{ad}_x (y) = [x,y]
for all "y" in mathfrak{g}.
adx is an action that is
linear .Adjoint representation
The mapping extrm{ad}:mathfrak{g} ightarrow extrm{End}(mathfrak{g})=mathfrak{gl}(mathfrak{g}) given by xmapsto extrm{ad}_x is a
representation of a Lie algebra and is called the adjoint representation of the algebra. (Here, mathfrak{gl}(mathfrak{g}) is the Lie algebra of thegeneral linear group over the vector space mathfrak{g}. It is isomorphic to extrm{End}(mathfrak{g}).)Within mathfrak{gl}(mathfrak{g}), the composition of two maps is well defined, and the
Lie bracket may be shown to be given by the commutator of the two elements, :extrm{ad}_x, extrm{ad}_y] = extrm{ad}_x circ extrm{ad}_y - extrm{ad}_y circ extrm{ad}_xwhere circ denotes composition of linear maps. If a basis is chosen for mathfrak{g}, this corresponds tomatrix multiplication .Using this and the definition of the Lie bracket in terms of the mapping "ad" above, the
Jacobi identity :x, [y,z] + [y, [z,x] + [z, [x,y] =0 takes the form :left( [ extrm{ad}_x, extrm{ad}_y] ight)(z) = left( extrm{ad}_{ [x,y] } ight)(z)where "x", "y", and "z" are arbitrary elements of mathfrak{g}.This last identity confirms that "ad" really is a Lie algebra homomorphism, in that the morphism "ad" commutes with the multiplication operator [,] .
The kernel of operatorname{ad}: mathfrak{g} o operatorname{ad}(mathfrak{g}) is, by definition, the center of mathfrak{g}.
Derivation
A derivation on a Lie algebra is a
linear map delta:mathfrak{g} ightarrow mathfrak{g} that obeys theLeibniz' law , that is,:delta ( [x,y] ) = [delta(x),y] + [x, delta(y)] for all "x" and "y" in the algebra.
That adx is a derivation is a consequence of the Jacobi identity. This implies that the image of mathfrak{g} under "ad" is a subalgebra of operatorname{Der}(mathfrak{g}), the space of all derivations of mathfrak{g}.
tructure constants
The explicit matrix elements of the adjoint representation are given by the
structure constant s of the algebra. That is, let {ei} be a set ofbasis vectors for the algebra, with :e^i,e^j] ={c^{ij_k e^k. Then the matrix elements for adeiare given by:left [ extrm{ad}_{e^i} ight] _k}^j = {c^{ij_k .Thus, for example, the adjoint representation of so(3) is su(2).
Relation to Ad
Ad and ad are related through the
exponential map ; crudely, Ad = exp ad, where Ad is theadjoint representation for aLie group .To be precise, let "G" be a Lie group, and let Psi:G ightarrow extrm{Aut} (G) be the mapping gmapsto Psi_g with Psi_g:G o G given by the
inner automorphism :Psi_g(h)= ghg^{-1}.This is called the Lie group map. Define extrm{Ad}_g to be the derivative of Psi_g at the origin::extrm{Ad}(g) = (dPsi_g)_e : T_eG ightarrow T_eGwhere "d" is the differential and "T"eG is thetangent space at the origin "e" ("e" is the identity element of the group "G").The Lie algebra "g" of "G" is "g"="T"eG. Since extrm{Ad}_gin extrm{Aut}(mathfrak{g}), extrm{Ad}:gmapsto extrm{Ad}_g is a map from "G" to Aut("T"e"G") which will have a derivative from "T"e"G" to End("T"e"G") (the Lie algebra of Aut("V") is End("V")).
Then we have :extrm{ad} = d( extrm{Ad})_e:T_eG ightarrow extrm{End} (T_eG).
The use of upper-case/lower-case notation is used extensively in the literature. Thus, for example, a vector "x" in the algebra mathfrak{g} generates a
vector field "X" in the group "G". Similarly, the adjoint map adxy= ["x","y"] of vectors in mathfrak{g} is homomorphic to theLie derivative L"X""Y" = ["X","Y"] of vector fields on the group "G" considered as amanifold .References
*Fulton-Harris
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