MacLaurin's inequality

MacLaurin's inequality

In mathematics, MacLaurin's inequality, named after Colin Maclaurin, is a refinement of the inequality of arithmetic and geometric means.

Let "a"1, "a"2, ..., "a""n" be positive real numbers, and for "k" = 1, 2, ..., "n" define the averages "S""k" as follows:

: S_k = frac{displaystyle sum_{ 1leq i_1 < cdots < i_k leq n}a_{i_1} a_{i_2} cdots a_{i_k{displaystyle {n choose k.

The numerator of this fraction is the elementary symmetric polynomial of degree "k" in the "n" variables "a"1, "a"2, ..., "a""n", that is, the sum of all products of "k" of the numbers "a"1, "a"2, ..., "a""n" with the indices in increasing order. The denominator is the number of terms in the numerator, the binomial coefficient scriptstyle {nchoose k}.

MacLaurin's inequality states that the following chain of inequalities is true:

: S_1 geq sqrt{S_2} geq sqrt [3] {S_3} geq cdots geq sqrt [n] {S_n}

with equality if and only if all the "a""i" are equal.

For "n" = 2, this gives the usual inequality of arithmetic and geometric means of two numbers. MacLaurin's inequality is well illustrated by the case "n" = 4:

: egin{align}& {} quad frac{a_1+a_2+a_3+a_4}{4} \ \& {} ge sqrt{frac{a_1a_2+a_1a_3+a_1a_4+a_2a_3+a_2a_4+a_3a_4}{6 \ \& {} ge sqrt [3] {frac{a_1a_2a_3+a_1a_2a_4+a_1a_3a_4+a_2a_3a_4}{4 \ \& {} ge sqrt [4] {a_1a_2a_3a_4}.end{align}

Maclaurin's inequality can be proved using the Newton's inequalities.

ee also

* Newton's inequalities
* Muirhead's inequality
* Generalized mean inequality

References

*cite book
last = Biler
first = Piotr
coauthors = Witkowski, Alfred
title = Problems in mathematical analysis
publisher = New York, N.Y.: M. Dekker
date = 1990
pages =
isbn = 0824783123

External links

* [http://mcraefamily.com/MathHelp/BasicNumberIneq.htm Famous Inequalities]

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