Burnside ring

In mathematics, the Burnside ring of a finite group is an algebraic construction that encodes the different ways the group can act on finite sets. The ideas were introduced by William Burnside at the end of the nineteenth Century, but the algebraic ring structure is a more recent development.

Formal definition

Given a finite group "G", the elements of its Burnside ring "Ω"("G") are the formal differences of isomorphism classes of finite "G"-sets. For the ring structure, addition is given by disjoint union of "G"-sets, and multiplication by their Cartesian product.

The Burnside ring is a free Z-module, whose generators are the (isomorphism classes of) orbit types of "G".

If "G" acts on a finite set "X", then one can write $X\; =\; cup\_i\; X\_i$ (disjoint union), where each "X"_"i" is a single "G"-orbit. Choosing any element "x"_"i" in "X"_i creates an isomorphism "G"/"G"_"i" → "X"_"i", where "G_i" is the stabilizer (isotropy) subgroup of "G" at "x"_"i". A different choice of representative "y"_"i" in "X"_"i" gives a conjugate subgroup to "G"_"i" as stabilizer. This shows that the generators of "Ω(G)" as a Z-module are the orbits "G"/"H" as "H" ranges over conjugacy classes of subgroups of "G".

In other words, a typical element of "Ω"("G") is:$sum\_\{i=1\}^N\; a\_i\; [G/G\_i]\; ,$where "a"_"i" in Z and "G"₁, "G"₂, ... , "G"_"N" are representatives of the conjugacy classes of subgroups of "G".

Marks

Much like character theory simplifies working with group representations, marks simplify working with permutation representations and the Burnside ring.

If "G" acts on "X", and "H" ≤ "G" ("H" is a subgroup of "G"), then the mark of "H" on "X" is the number of elements of "X" that are fixed by every element of "H": $m\_X(H)\; =\; left|X^H\; ight|$, where:$X^H\; =\; \{\; xin\; X\; mid\; hcdot\; x\; =\; x,\; forall\; hin\; H\}.$If "H" and "K" are conjugate subgroups, then "m"_"X"("H") = "m"_"X"("K") for any finite "G"-set "X"; indeed, if "K" = "gHg"⁻¹ then "X"^"K" = "g" · "X"^"H".

It is also easy to see that for each "H" ≤ "G", the map "Ω"("G") → Z : "X" ↦ "m"_"X"("H") is a homomorphism. This means that to know the marks of "G", it is sufficient to evaluate them on the generators of "Ω"("G"), "viz." the orbits "G"/"H".

For each pair of subgroups "H","K" ≤ "G" define:$m(K,\; H)\; =\; left|\; [G/K]\; ^H\; ight|\; =\; \#\; left\{\; gK\; in\; G/K\; mid\; HgK=gK\; ight\}.$This is "m"_"X"("H") for "X" = "G"/"K". The condition "HgK" = "gK" is equivalent to "g"⁻¹"Hg" ≤ "K", so if "H" is not conjugate to a subgroup of "K" then "m"("K", "H") = 0.

To record all possible marks, one forms a table, Burnside's Table of Marks, as follows: Let "G"₁ (= trivial subgroup), "G"₂, ... , "G"_"N" = "G" be representatives of the "N" conjugacy classes of subgroups of "G", ordered in such a way that whenever "G"_"i" is conjugate to a subgroup of "G"_"j", then "i" ≤ "j". Now define the "N" × "N" table (square matrix) whose ("i", "j")th entry is "m"("G"_"i", "G"_"j"). This matrix is lower triangular, and the elements on the diagonal are non-zero so it is invertible.

It follows that if "X" is a "G"-set, and u its row vector of marks, so "u"_"i" = "m"_"X"("G"_"i"), then "X" decomposes as a disjoint union of "a"_"i" copies of the orbit of type "G"_"i", where the vector a satisfies,:a"M" = "u",where "M" is the matrix of the table of marks. This theorem is due to harv|Burnside|1897.

Examples

The table of marks for the cyclic group of order 6:

The table of marks for the symmetric group "S₃" on 3 letters:

The dots in the two tables are all zeros, merely emphasizing the fact that the tables are lower-triangular.

(Some authors use the transpose of the table, but this is how Burnside defined it originally.)

The fact that the last row is all 1s is because ["G"/"G"] is a single point. The diagonal terms are "m"("H", "H") = | "N"_"G"("H")/"H" |.

The ring structure of "Ω"("G") can be deduced from these tables: the generators of the ring (as a Z-module) are the rows of the table, and the product of two generators has mark given by the product of the marks (so component-wise multiplication of row vectors), which can then be decomposed as a linear combination of all the rows. For example, with "S"₃,:$[G/mathbf\{Z\}\_2]\; cdot\; [G/mathbf\{Z\}\_3]\; =\; [G/1]\; ,$as (3, 1, 0, 0).(2, 0, 2, 0) = (6, 0, 0, 0).

Permutation representations

Associated to any finite set "X" is a vector space "V = V_X", which is the vector space with the elements of "X" as the basis (using any specified field). An action of a finite group "G" on "X" induces a linear action on "V", called a permutation representation. The set of all finite dimensional representations of "G" has the structure of a ring, the representation ring, denoted "R(G)".

For a given "G"-set "X", the character of the associated representation is

:$chi(g)\; =\; m\_X(langle\; g\; angle)$

where <"g"> is the cyclic group generated by "g".

The resulting
taking a "G"-set to the corresponding representation is in general neither injective nor surjective.

The simplest example showing that &beta; is not in general injective is for "G = S₃" (see table above), and is given by:

Extensions

The Burnside ring for compact groups is described in harv|tom Dieck|1987.

The Segal conjecture relates the Burnside ring to homotopy.

References

*Citation | last1=Burnside | first1=William | author1-link=William Burnside | title=Theory of groups of finite order | publisher=Cambridge University Press | year=1897
*Citation | last1=tom Dieck | first1=Tammo | title=Transformation groups | publisher=Walter de Gruyter | series=de Gruyter Studies in Mathematics | isbn=978-3-11-009745-0 | id=MathSciNet | id = 889050 | year=1987 | volume=8 | ISBN status=May be invalid - please double check
*Citation | last1=Kerber | first1=Adalbert | title=Applied finite group actions | publisher=Springer-Verlag | location=Berlin, New York | edition=2nd | series=Algorithms and Combinatorics | isbn=978-3-540-65941-9 | id=MathSciNet | id = 1716962 | year=1999 | volume=19 | ISBN status=May be invalid - please double check