- Hamburger moment problem
In
mathematics , the Hamburgermoment problem , named after Hans Ludwig Hamburger, is formulated as follows: given a sequence { "αn" : "n" = 1, 2, 3, ... }, does there exist a positiveBorel measure "μ" on the real line such that:
In other words, an affirmative answer to the problem means that { "αn" : "n" = 0, 1, 2, ... } is the sequence of moments of some positive Borel measure "μ".
The
Stieltjes moment problem ,Vorobyev moment problem , and theHausdorff moment problem are similar but replace the real line by [0, +∞) (Stieltjes and Vorobyev; but Vorobyev formulates the problem in the terms of matrix theory), or a bounded interval (Hausdorff).Characterization
The Hamburger moment problem is solvable, that is, {"αn"} is a sequence of moments, if and only if the corresponding Hankel kernel on the nonnegative integers
:
is positive definite, i.e.,
:
for an arbitrary sequence {"cj"}"j ≥ 0" of complex numbers with finite support, i.e. "cj" = 0 except for finitely many values of "j".
The "only if" part of the claims can be verified by a direct calculation.
We sketch an argument for the converse. Let Z+ be the nonnegative integers and "F"0(Z+) denote the family of complex valued sequences with finite support. The positive Hankel kernel "A" induces a (possibly degenerate)
sesquilinear product on the family of complex valued sequences with finite support. This in turn gives aHilbert space :
whose typical element is an equivalence class denoted by ["f"] .
Let "en" be the element in "F"0(Z+) defined by "en"("m") = "δnm". One notices that
:
Therefore the "shift" operator "T" on , with "T" ["en"] = ["e""n" + 1] , is symmetric.
On the other hand, the desired expression
: suggests that "μ" is the
spectral measure of aself-adjoint operator . If we can find a "function model" such that the symmetric operator "T" is multiplication by "x", then the spectral resolution of a self-adjoint extension of "T" proves the claim.A function model is given by the natural isomorphism from "F"0(Z+) to the family of polynomials, in one single real variable and complex coefficients: for "n" ≥ 0, identify "en" with "xn". In the model, the operator "T" is multiplication by "x" and a densely defined symmetric operator. It can be shown that "T" always has self-adjoint extensions. Let
:
be one of them and "μ" be its spectral measure. So
:
On the other hand,
:
Uniqueness of solutions
The solutions form a convex set, so the problem has either infinitely many solutions or a unique solution.
Consider the ("n" + 1)×("n" + 1)
Hankel matrix :
Positivity of "A" means that for each "n", det(Δ"n") ≥ 0. If det(Δ"n") = 0, for some "n", then
:
is finite dimensional and "T" is self-adjoint. So in this case the solution to the Hamburger moment problem is unique and "μ", being the spectral measure of "T", has finite support.
More generally, the solution is unique if there are constants "C" and "D" such that for all "n", |α"n"|≤ "CD""n""n"! harv|Reed|Simon|1975|p=205.
There are examples where the solution is not unique.
Further results
One can see that the Hamburger moment problem is intimately related to
orthogonal polynomials on the real line. TheGram-Schmidt procedure gives a basis of orthogonal polynomials in which the operator:
has a tridiagonal "Jacobi matrix representation". This in turn leads to a "tridiagonal model" of positive Hankel kernels.
An explicit calculation of the
Cayley transform of "T" shows the connection with what is called the "Nevanlinna class" of analytic functions on the left half plane. Passing to the non-commutative setting, this motivates "Krein's formula" which parametrizes the extensions of partial isometries.References
*citation|first=Michael|last=Reed|first2=Barry|last2=Simon|title=Fourier Analysis, Self-Adjointness|year=1975|ISBN=0-12-585002-6|series=Methods of modern mathematical physics|volume=2|publisher=Academic Press|page=145, 205
*.
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