Mauritian general election, 1967

Mauritian general election, 1967
Mauritius

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General elections were held in Mauritius on 7 August 1967. The result was a victory for the Independence Party led by the Labour Party, which won a total of 43 seats,[1] allowing Labour leader and incumbent Prime Minister Seewoosagur Ramgoolam to form a government.

The voting system created twenty constituencies on Mauritius, which each elected three members. Two seats were elected by residents of Rodrigues, and eight seats were filled by the "best losers".[2] Voter turnout was 88.9%.[3]

Results

Party Votes % Seats +/-
Constituency Best-loser Total
Independence Party* 444,262 54.6 39 4 43 +13
Mauritian Social Democrat Party 354,196 43.5 23 4 27 +19
All Mauritian Hindu Congress 15,459 1.9 0 0 0 0
Mauritius Liberation Front 0 0 0 0
Mauritius Workers Party 0 0 0 0
Mauritius Young Communist League 0 0 0 0
National Socialist Workers Party 0 0 0 0
Rodrigues Party 0 0 0 0
Total 813,917 100 62 8 70 +30
Source: Nohlen et al

* The Independence Party bloc consisted of the Labour Party (26 seats), the Independent Forward Bloc (12 seats) and the Muslim Committee of Action (5 seats).

References

  1. ^ Nohlen, D, Krennerich, M & Thibaut, B (1999) Elections in Africa: A data handbook, p618 ISBN 0198296452
  2. ^ Mauritius: Background to the 1967 Legislative Assembly election EISA
  3. ^ Mauritius: 1967 Legislative Assembly election results overview EISA

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