- Mauritian general election, 1967
-
Mauritius
This article is part of the series:
Politics and government of
MauritiusGovernment- President (List)
- Vice President
- Prime Minister (List)
Parliament- National Assembly
- Lord Speaker
- Rajkeswur Purryag
- The Cabinet
- Lord Speaker
- MPs
The OppositionElectionsPolitical Parties
General elections were held in Mauritius on 7 August 1967. The result was a victory for the Independence Party led by the Labour Party, which won a total of 43 seats,[1] allowing Labour leader and incumbent Prime Minister Seewoosagur Ramgoolam to form a government.
The voting system created twenty constituencies on Mauritius, which each elected three members. Two seats were elected by residents of Rodrigues, and eight seats were filled by the "best losers".[2] Voter turnout was 88.9%.[3]
Results
Party Votes % Seats +/- Constituency Best-loser Total Independence Party* 444,262 54.6 39 4 43 +13 Mauritian Social Democrat Party 354,196 43.5 23 4 27 +19 All Mauritian Hindu Congress 15,459 1.9 0 0 0 0 Mauritius Liberation Front 0 0 0 0 Mauritius Workers Party 0 0 0 0 Mauritius Young Communist League 0 0 0 0 National Socialist Workers Party 0 0 0 0 Rodrigues Party 0 0 0 0 Total 813,917 100 62 8 70 +30 Source: Nohlen et al * The Independence Party bloc consisted of the Labour Party (26 seats), the Independent Forward Bloc (12 seats) and the Muslim Committee of Action (5 seats).
References
- ^ Nohlen, D, Krennerich, M & Thibaut, B (1999) Elections in Africa: A data handbook, p618 ISBN 0198296452
- ^ Mauritius: Background to the 1967 Legislative Assembly election EISA
- ^ Mauritius: 1967 Legislative Assembly election results overview EISA
Elections in Mauritius General elections Categories:- Elections in Mauritius
- 1967 in Mauritius
- 1967 elections in Africa
Wikimedia Foundation. 2010.