Douglas Township, Saunders County, Nebraska

Douglas Township, Saunders County, Nebraska
Douglas Township
—  Township  —
Location in Saunders County
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694
Country United States
State Nebraska
County Saunders
Area
 – Total 32.01 sq mi (82.91 km2)
 – Land 32.01 sq mi (82.91 km2)
 – Water 0 sq mi (0 km2)  0%
Elevation 1,309 ft (399 m)
Population (2000)
 – Total 196
 – Density 6.1/sq mi (2.4/km2)
GNIS feature ID 0837967

Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]

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