1s Slater-type function

1s Slater-type function

A normalized 1s Slater-type function is a function which has the form

:psi_{1s}(zeta, mathbf{r - R}) = left(frac{zeta^3}{pi} ight)^{1 over 2} , e^{-zeta |mathbf{r - R}. [cite book
last = Attila Szabo and Neil S. Ostlund
first =
title = Modern Quantum Chemistry - Introduction to Advanced Electronic Structure Theory
publisher = Dover Publications Inc.
year = 1996
pages = 153
isbn = 0486691861
]

The parameter zeta is called the Slater orbital exponent. Related sets of functions can be used to construct STO-nG basis sets which are used in quantum chemistry.

Applications for hydrogen-like atomic systems

A hydrogen-like atom or a hydrogenic atom is an atom with one electron. Except for the hydrogen atom itself (which is neutral) these atoms carry positive charge e(mathbf Z-1), where mathbf Z is the atomic number of the atom. Because hydrogen-like atoms are two-particle systems with an interaction depending only on the distance between the two particles, their (non-relativistic) Schrödinger equation can be exactly solved in analytic form. The solutions are one-electron functions and are referred to as "hydrogen-like atomic orbitals". [In quantum chemistry an orbital is synonymous with "one-electron function", i.e., a function of "x", "y", and "z".] The electonic Hamiltonian (in atomic units) of a Hydrogenic system is given by
mathbf hat{H}_e = - frac{ abla^2}{2} - frac{mathbf Z}{r}, where mathbf Z is the nuclear charge of the hydrogenic atomic system. The 1s electron of a hydrogenic systems can be accurately described by the corresponding Slater orbital:
mathbf psi_{1s} = left (frac{zeta^3}{pi} ight ) ^{0.50}e^{-zeta r}, where mathbf zeta is the Slater exponent.

Exact energy of a hydrogen-like atom

The energy of a hydrogenic system can be exactly calculated analytically as follows :
mathbf E_{1s} = frac{}{}, where mathbf = 1
mathbf E_{1s} =
mathbf E_{1s} = +
mathbf E_{1s} = +. Using the expression for Slater orbital, mathbf psi_{1s} = left (frac{zeta^3}{pi} ight ) ^{0.50}e^{-zeta r} the integrals can be exactly solved. Thus,
mathbf E_{1s} = + Integrals needed int_0^infty e^{-alpha r^2}r^n,dr = frac{(n-1)!!}{2^n/2} +1} alpha^{n/2sqrt frac{pi}{alpha} when 'n' is even. int_0^infty e^{-alpha r^2}r^n,dr = frac{(frac{n-1}{2})!}{2 alpha^(n+1)}/2 when 'n' is odd.
mathbf E_{1s} = frac{zeta^2}{2}-zeta mathbf Z.

The optimum value for mathbf zeta is obtained by equating the differential of the energy with respect to mathbf zeta as zero.
frac{dmathbf E_{1s{dzeta}=zeta-mathbf Z=0. Thus mathbf zeta=mathbf Z.

Non relativistic energy

The following energy values are thus calculated by using the expressions for energy and for the Slater exponent.

Hydrogen : H
mathbf Z=1 and mathbf zeta=1
mathbf E_{1s}=−0.5 Eh
mathbf E_{1s}=−13.60569850 eV
mathbf E_{1s}=−313.75450000 kcal/mol

Gold : Au(78+)
mathbf Z=79 and mathbf zeta=79
mathbf E_{1s}=−3120.5 Eh
mathbf E_{1s}=−84913.16433850 eV
mathbf E_{1s}=−1958141.8345 kcal/mol.

Relativistic energy of Hydrogenic atomic systems

Hydrogenic atomic systems are suitable models to demonstrate the relativistic effects in atomic systems in a simple way. The energy expectation value can calculated by using the Slater orbitals with or without considering the relativistic correction for the Slater exponent mathbf zeta . The relativistically corrected Slater exponent mathbf zeta_{rel} is given as
mathbf zeta_{rel}= frac{mathbf Z}{sqrt {1-mathbf Z^2/c^2.
The relativistic energy of an electron in 1s orbital of a hydrogenic atomic systems is obtained by solving the Dirac equation.
mathbf E_{1s}^{rel} = -(c^2+mathbf Zzeta)+sqrt{c^4+mathbf Z^2zeta^2}.
Following table illustrates the relativistic corrections in energy and it can be seen how the relativistic correction scales with the atomic number of the system.

Atomic system mathbf Zmathbf zeta_{non rel}mathbf zeta_{rel}mathbf E_{1s}^{non rel}mathbf E_{1s}^{rel}using mathbf zeta_{non rel}mathbf E_{1s}^{rel}using mathbf zeta_{rel}
H11.000000001.00002663−0.50000000 Eh−0.50000666 Eh−0.50000666 Eh
−13.60569850 eV−13.60587963 eV−13.60587964 eV
−313.75450000 kcal/mol−313.75867685 kcal/mol−313.75867708 kcal/mol
Au(78+)7979.00000000 96.68296596−3120.50000000 Eh−3343.96438929 Eh−3434.58676969 Eh
−84913.16433850 eV −90993.94255075 eV −93459.90412098 eV
−1958141.83450000 kcal/mol−2098367.74995699 kcal/mol−2155234.10926142 kcal/mol

Notes


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