- Thermodynamics of the universe
The thermodynamics of the universe is dictated by which form of energy dominates it -
relativistic particle s which are referred to asradiation , or non-relativistic particles which are referred to as matter. The former are particles whoserest mass is zero or negligible compared to their energy, and therefore move at the speed of light or very close to it; The latter are particles whosekinetic energy is much lower than theirrest mass and therefore move much slower than the speed of light. The intermediate case is not treated well analytically.Energy density in the expanding universe
If the universe is not undergoing a
phase transition , one can approximate itsthermodynamics by neglecting interactions between particles, and assuming all theenergy is in the form ofheat . Then by thefirst law of thermodynamics :0 = dQ = dU + P dV
Where Q is the total heat which is assumed to be constant, U is the internal energy of the matter and radiation in the universe, P is the pressure and V the volume.
One then finds an equation for the
energy density uequiv U/Vdu = d({Uover V})={dUover V}-U{dVover V^2}=-(p+u){dVover V} = -3(p+u){daover a}where in the last equality we used the fact that the total volume of the universe is proportional to a^3, a being the scale factor of the universe.
In fact this equation can be directly obtained from the equations of motion governing the
Friedmann-Lemaître-Robertson-Walker metric : by dividing the equation above with dt and identifying ho = u (the energy density), we get one of the FLRW equations of motions.In the
comoving coordinates , u is equal to themass density ho. For radiation, p=u/3 whereas for matter p< and the pressure can be neglected. Thus we get:For radiationdu = -4u {daover a}thus u is proportional to a^{-4}
For matterdu = -3u {daover a}thus u is proportional to a^{-3}
This can be understood as follows: For matter, the
energy density is equal (in our approximation) to therest mass density. This is inversly proportional to the volume, and is therefore proportional to a^{-3}.Forradiation , theenergy density depends on thetemperature T as well, and is therefore proportional to T a^{-3}. As the universe expands it cools down, so T depends on a as well. In fact, since theenergy of arelativistic particle is inversely proportional to itswavelength , which is proportional to a, theenergy density of theradiation must be proportional to a^{-4}.From this discussion it is also obvious that the
temperature of radiation is inversely proportional to the scale factor a.Rate of expansion of the universe
Plugging this information to the Friedmann-Lemaître-Robertson-Walker
equations of motion and neglecting both thecosmological constant Lambda and the curvatue parameter k, which is justified for the early universe (a<<1), one gets the following equation:
dot a}^2} propto {a^2} ho
ho = u is the energy density, and one finds the following behavior::In a radiation-dominated universe a propto t^{1/2}:In a matter-dominated universe a propto t^{2/3}One can further show that the universe was radiation-dominated as long as the
energy density was of the order of 10eV to the fourth, or higher. Since theenergy density keeps going down, this was no longer true when the universe was 70,000 years old, when it .In the universe today, matter is mainly in forms of galaxies and
dark matter , while the radiation is thecosmic microwave background radiation , thecosmic neutrino background (if theneutrino rest mass is high enough then the latter is formally matter), and finally, mostly in the form ofdark energy .Dark energy and cosmic inflation
Dark energy is a hypothetical form of energy that permeates all of space, and causes an acceleration in the expansion of the universe due to its strongnegative pressure : ingeneral relativity ,pressure has a gravitational effect similar to that of energy and mass, and while positive pressure causes gravitational attraction and thus decelerates the expansion of the universe,negative pressure causes gravitational repulsion and thus accelerates the expansion of the universe.According to the equation above,:dot u} = -3(p+u)frac{dot a}{a}Thus the negative the pressure is, the less the enrgy density reduces as te universe expands. In other words,
Dark energy dilutes less than any other form of energy, and will therefore eventually dominate the universe, as all other energy densities gets diluted faster with the expansion of the universe.In fact, if the
dark energy is created by acosmological constant or a constant scalar field, then its pressure is minus its energy density p = -u, and therefore its energy density remains constant (as is expected by definition).Dark energy is usually assumed to be theCasimir energy of the vacuum, with possible contributions from the energy density of scalar fields which has a non-zero value at the vacuum. It may be that this field can decay at some time in the distant future, leading to a newvacuum state , different than the one we are living in. This is aphase transition , where thedark energy is reduced and huge amounts of energy in conventional forms (i.e. particles) are produced.Such a series of events is in fact thought to have already occurred in the early universe, where first a
cosmological constant much larger than the present one came to dominate the universe, bringing aboutcosmic inflation . At the end of this epoch, aphase transition occurred where thecosmological constant was reduced to its present value and huge amounts of energy where produced, from which all the radiation and matter of the early universe came about.ee also
*
Physical cosmology
*Friedmann-Lemaître-Robertson-Walker metric
*Dark energy
*Cosmic inflation
*Thermodynamics
*First law of thermodynamics
Wikimedia Foundation. 2010.