Integral of secant cubed

Integral of secant cubed

One of the more challenging indefinite integrals of elementary calculus is

:int sec^3 x , dx = frac{1}{2}sec x an x + frac{1}{2}ln|sec x + an x| + C.

There are a number of reasons why this particular antiderivative is worthy of special attention:

* The technique used for reducing integrals of higher odd powers of secant to lower ones is fully present in this, the simplest case. The other cases are done in the same way.

* This is one of several integrals usually done in a first-year calculus course in which the most natural way to proceed involves integrating by parts and returning to the same integral one started with (another is the integral of the product of an exponential function with a sine or cosine function; yet another the integral of a power of the sine or cosine function).

* This integral appears in the problem of rectifying (i.e. finding the arc length of) the parabola.

* This integral appears in the problem of finding the surface area of the helicoid.

Derivation

This antiderivative may be found by integration by parts, as follows:

: int sec^3 x , dx = int u,dv

where

:egin{align}u &{}= sec x, \dv &{}= sec^2 x,dx, \du &{}= sec x an x,dx, \v &{}= an x.end{align}

Then

:egin{align}int sec^3 x , dx &{}= int u,dv \&{}= uv - int v,du \&{} = sec x an x - int sec x an^2 x,dx \&{}= sec x an x - int sec x, (sec^2 x - 1),dx \&{}= sec x an x - int sec^3 x , dx + int sec x,dx.end{align}

Next we add scriptstyle{}intsec^3 x,dx to both sides of the equality just derived:

:egin{align}2 int sec^3 x , dx &{}= sec x an x + int sec x,dx \&{}= sec x an x + ln|sec x + an x| + C.end{align}

Then divide both sides by 2:

:int sec^3 x , dx = frac{1}{2}sec x an x + frac{1}{2}ln|sec x + an x| + C.

Higher odd powers of secant

Just as the integration by parts above reduced the integral of secant cubed to the integral of secant to the first power, so a similar process reduces the integral of higher odd powers of secant to lower ones. This is the secant reduction formula, which follows the syntax:

: int sec^n x , dx = frac{sec^{n-2} x an x}{n-1} ,+, frac{n-2}{n-1}int sec^{n-2} x , dx qquad ext{ (for }n e 1 ext{)},!

Alternatively:

: int sec^n x , dx = frac{sec^{n-1} x sin x}{n-1} ,+, frac{n-2}{n-1}int sec^{n-2} x , dx qquad ext{ (for }n e 1 ext{)},!

See also

* Table of integrals


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