- Angular velocity
:"Do not confuse with

angular frequency "The unit for angular velocity is rad/s.

In

physics , the**angular velocity**is a vector quantity (more precisely, apseudovector ) which specifies theangular speed , and axis about which an object is rotating. TheSI unit of angular velocity isradians per second , although it may be measured in other units such as degrees per second, degrees per hour, etc. When measured in cycles or rotations per unit time (e.g.revolutions per minute ), it is often called the rotational velocity and its magnitude therotational speed . Angular velocity is usually represented by the symbolomega (**Ω**or**ω**). The direction of the angular velocity vector is perpendicular to the plane of rotation, in a direction which is usually specified by theright hand rule .**The angular velocity of a particle****Two dimensions**The angular velocity of a particle in a 2-dimensional plane is the easiest to understand. As shown in the figure on the right (typically expressing the angular measures "φ" and "θ" in

radian s), if we draw a line from the origin (O) to the particle (P), then the velocity vector (**v**) of the particle will have a component along the radius (radial component ,**v**_{∥}) and a component perpendicular to the radius (tangential component ,**v**_{⟂}).A radial motion produces no rotation of the particle (relative to the origin), so for purposes of finding the angular velocity the parallel (radial) component can be ignored. Therefore, the rotation is completely produced by the tangential motion (like that of a particle moving along a circumference), and the angular velocity is completely determined by the perpendicular (tangential) component.

It can be seen that the rate of change of the angular position of the particle is related to the tangential velocity by::$mathrm\{v\}\_perp=r,frac\{dphi\}\{dt\}$Utilizing "θ", the angle between vectors

**v**_{∥}and**v**, or equivalently as the angle between vectors**r**and**v**, gives::$mathrm\{v\}\_perp=|mathrm\{mathbf\{v|,sin(\; heta).$Combining the above two equations and defining the angular velocity as ω=dφ/dt yields::$omega=frac,hat\{n\}$

which, by the definition of the

cross product , can be written::$oldsymbolomega=frac\{mathbf\{r\}\; imesmathbf\{v\{|mathrm\{mathbf\{r|^2\}$

**Higher dimensions**In general, the angular velocity in an n-dimensional space is the time derivative of the angular displacement tensor which is a second rank

skew-symmetric tensor. This tensor will have n(n-1)/2 independent components and this number is the dimension of theLie algebra of theLie group ofrotations of an "n"-dimensional inner product space. [*http://math.ucr.edu/home/baez/classical/galilei2.pdf Rotations and Angular Momentum*] on the Classical Mechanics page of [*http://math.ucr.edu/home/baez/README.html the website of John Baez*] , especially Questions 1 and 2.] It turns out that in three dimensional space angular velocity can be represented by vector because number of independent components is equal to number of dimensions of space.**Angular velocity of a rigid body**In order to deal with the motion of a

rigid body , it is best to consider a coordinate system that is fixed with respect to the rigid body, and to study the coordinate transformations between this coordinate and the fixed "laboratory" system. As shown in the figure on the right, the lab system's origin is at point O, the rigid body system origin is at O' and the vector from O to O' is**R**. A particle ("i") in the rigid body is located at point P and the vector position of this particle is**R**_{i}in the lab frame, and at position**r**_{i}in the body frame. It is seen that the position of the particle can be written::$mathbf\{R\}\_i=mathbf\{R\}+mathbf\{r\}\_i$

The defining characteristic of a rigid body is that the distance between any two points in a rigid body is unchanging in time. This means that the length of the vector $mathbf\{r\}\_i$ is unchanging. By

Euler's rotation theorem , we may replace the vector $mathbf\{r\}\_i$ with $mathcal\{R\}mathbf\{r\}\_\{io\}$ where $mathcal\{R\}$ is arotation matrix and $mathbf\{r\}\_\{io\}$ is the position of the particle at some fixed point in time, say t=0. This replacement is useful, because now it is only the rotation matrix $mathcal\{R\}$ which is changing in time and not the reference vector $mathbf\{r\}\_\{io\}$, as the rigid body rotates about point O'. The position of the particle is now written as::$mathbf\{R\}\_i=mathbf\{R\}+mathcal\{R\}mathbf\{r\}\_\{io\}$

Taking the time derivative yields the velocity of the particle:

:$mathbf\{V\}\_i=mathbf\{V\}+frac\{dmathcal\{R\{dt\}mathbf\{r\}\_\{io\}$

where

**V**_{i}is the velocity of the particle (in the lab frame) and**V**is the velocity of O' (the origin of the rigid body frame). Since $mathcal\{R\}$ is a rotation matrix its inverse is its transpose. So we substitute $mathcal\{I\}=mathcal\{R\}^Tmathcal\{R\}$::$mathbf\{V\}\_i=mathbf\{V\}+frac\{dmathcal\{R\{dt\}mathcal\{I\}mathbf\{r\}\_\{io\}$

:$mathbf\{V\}\_i=mathbf\{V\}+frac\{dmathcal\{R\{dt\}mathcal\{R\}^Tmathcal\{R\}mathbf\{r\}\_\{io\}$

:$mathbf\{V\}\_i=mathbf\{V\}+frac\{dmathcal\{R\{dt\}mathcal\{R\}^Tmathbf\{r\}\_\{i\}$

Continue by taking the time derivitve of $mathcal\{R\}mathcal\{R\}^T$:

:$mathcal\{I\}=mathcal\{R\}mathcal\{R\}^T$

:$0=frac\{dmathcal\{R\{dt\}mathcal\{R\}^T+mathcal\{R\}frac\{dmathcal\{R\}^T\}\{dt\}$

Applying the formula (

**AB**)^{T}=**B**^{T}**A**^{T}::$0=frac\{dmathcal\{R\{dt\}mathcal\{R\}^T+(frac\{dmathcal\{R\{dt\}mathcal\{R\}^T)^T$

$frac\{dmathcal\{R\{dt\}mathcal\{R\}^T$ is the negative of its transpose. Therefore it is a skew symmetric 3x3 matrix. We can therefore take its dual to get a 3 dimensional vector. $frac\{dmathcal\{R\{dt\}mathcal\{R\}^T$ is called the

angular velocity tensor . If we take the dual of this tensor, matrix multiplication is replaced by the cross product. Its dual is called the angular velocity pseudovector, ω.:$oldsymbolomega=\; [omega\_x,omega\_y,omega\_z]$

Substituting ω into the above velocity expression:

:$mathbf\{V\}\_i=mathbf\{V\}+oldsymbolomega\; imesmathbf\{r\}\_i.$

It can be seen that the velocity of a point in a rigid body can be divided into two terms - the velocity of a reference point fixed in the rigid body plus the cross product term involving the angular velocity of the particle with respect to the reference point. This angular velocity is the "spin" angular velocity of the rigid body as opposed to the angular velocity of the reference point O' about the origin O.

It is an

**important point**that the spin angular velocity of every particle in the rigid body is the same, and that the spin angular velocity is independent of the choice of the origin of the rigid body system or of the lab system. In other words, it is a physically real quantity which is a property of the rigid body, independent of one's choice of coordinate system. The angular velocity of the reference point about the origin of the lab frame will, however, depend on these choices of coordinate system. It is often convenient to choose thecenter of mass of the rigid body as the origin of the rigid body system, since a considerable mathematical simplification occurs in the expression for theangular momentum of the rigid body.**ee also***

Angular frequency

*Angular acceleration

*Angular momentum

*Areal velocity

*Isometry

*Lie algebra

*Orthogonal group

*Rigid body dynamics

*Rotation group **References***cite book|last=Symon | first=Keith |title=Mechanics|publisher=Addison-Wesley, Reading, MA|year=1971|id = ISBN 0-201-07392-7

*cite book |last=Landau |first=L.D. |authorlink=Lev Landau |coauthors=Lifshitz, E.M. |title= Mechanics|year=1997 |publisher=Butterworth-Heinemann |isbn=0-750-62896-0

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