- Polar moment of inertia
Polar moment of inertia is a quantity used to predict an object's ability to resist torsion, in objects (or segments of objects) with an invariant circular
cross-section and no significant warping or out-of-plane deformation.Ugural AC, Fenster SK. Advanced Strength and Applied Elasticity. 3rd Ed. Prentice-Hall Inc. Englewood Cliffs, NJ. 1995. ISBN 0-13-137589-X.] It is used to calculate theangular displacement of an object subjected to atorque . It is analogous to thearea moment of inertia , which characterizes an object's ability to resistbending and is required to calculatedisplacement .The larger the polar moment of inertia, the less the beam will twist, when subjected to a given torque.
Polar moment of inertia should not be confused with
moment of inertia , which characterizes an object'sangular acceleration due to atorque . Seemoment (physics) .Limitations
In objects with significant cross-sectional variation, which cannot be analyzed in segments, and/or a non-circular cross-section a more complex approach has to be used. See
3-D elasticity .Definition
:
* "J""z" = the polar moment of inertia about the axis "z"
* "dA" = an elemental area
* "ρ" = the radial distance to the element "dA" from the axis "z"For a circular section with radius r:
:
For a rectangular section with sides b and h:
:
Unit
The
SI unit for polar moment of inertia, like the "area moment of inertia", ismeter to the fourth power ("m"4)Application
The polar moment of area appears in the formulae that describes torsional stress and angular displacement.
Torsional stress:
:
where is the torque, is the radius and is the polar moment of area.
In a circular shaft, the shear stress is maximal at the surface of the shaft (as that is where the torque is maximal):
:
Most frequently the inverse problem is solved, in which one solves for the radius.
ample calculation
Calculation of the
steam turbine shaft radius for a turboset:Assumptions:
*Power carried by the shaft is 1000 MW; this is typical for a largenuclear power plant.
*Yield stress of the steel used to make the shaft (τyield) is: 250 x 106 N/m².
*Electricity has a frequency of 50 Hz; this is the typical frequency in Europe. In North America the frequency is 60 Hz.The
angular frequency can be calculated with the following formula::
The torque carried by the shaft is related to the power by the following equation:
:
The angular frequency is therefore 314.16 rad/s and the torque 3.1831 x 106 Nm.
The maximal torque is:
:
After substitution of the "polar moment of inertia" the following expression is obtained:
:
The
radius is 0.200 m. If one adds afactor of safety of 5 and re-calculates the radius with the maximal stress equal to the "yield stress/5" the result is a radius of 0.343 m, or adiameter of 69 cm, the approximate size of a turboset shaft in a nuclear power plant.Comparing various moments of inertias for a cylinder
Polar moment of inertia
: or: where:
*"d" is thediameter Area moment of inertia
: or:
Moment of inertia
: or:
ee also
*
Torsion spring
*Torsion bar
*Area moment of inertia References
External links
* [http://www.engineeringtoolbox.com/torsion-shafts-d_947.html Torsion of Shafts] - engineeringtoolbox.com
* [http://www.engineeringtoolbox.com/young-modulus-d_417.html Elastic Properties and Young Modulus for some Materials] - engineeringtoolbox.com
* http://mywebsite.bigpond.com/npajkic/solid_mechanics/polar_moments_and_products_of_inertia/index.html - Polar moments and products of inertia and the accompanying parallel-axis theorems
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