- Totally bounded space
In
topology and related branches ofmathematics , a totally bounded space is a space that can be covered by finitely manysubset s of any fixed "size" (where the meaning of "size" depends on the given context). The smaller the size fixed, the more subsets may be needed, but any specific size should require only finitely many subsets. A related notion is a totally bounded set, in which only a subset of the space needs to be covered. Every subset of a totally bounded space is a totally bounded set; but even if a space is not totally bounded, still some of its subsets will be. The term precompact (or pre-compact) is also used with the same meaning; but this terms is also used to meanrelatively bounded (which is equivalent in a complete metric space); see also#Use of the axiom of choice below.Definitions
The general logical form of the
definition is: A subset S of a space X is a totally bounded setif and only if ,given any size E,there exist anatural number n and a family A1, A2, ..., An of subsets of X, such that S is contained in the union of the family (in other words, the family is a "finite cover" of S), and such that each set Ai in the family is of size E (or less). Inmathematical symbols :: The space X is a totally bounded space if and only if it is a totally bounded set when considered as a subset of itself.(One can also define totally bounded spaces directly, and then define a set to be totally bounded if and only if it is totally bounded when considered as a subspace.)The terms "space" and "size" here are vague, and they may be made precise in various ways:
A subset S of a
metric space X is totally bounded if and only if, given any positivereal number E, there exists a finite cover of S by subsets of X whosediameter s are all less than E. (In other words, a "size" here is a positive real number, and a subset is of size E if its diameter is less than E.) Equivalently, S is totally bounded if and only if, given any E as before, there exist elements a1, a2, ..., an of X such that S is contained in the union of the nopen ball s of radius E around the points ai.A subset S of a
topological vector space , or more generallytopological abelian group , X is totally bounded if and only if, given any neighbourhood E of the identity (zero) element of X, there exists a finite cover of S by subsets of X each of which is a translate of a subset of E. (In other words, a "size" here is a neighbourhood of the identity element, and a subset is of size E if it is translate of a subset of E.) Equivalently, S is totally bounded if and only if, given any E as before, there exist elements a1, a2, ..., an of X such that S is contained in the union of the n translates of E by the points ai.A
topological group X is "left"-totally bounded if and only if it satisfies the definition for topological abelian groups above, using "left" translates. That is, use aiE in place of E + ai. Alternatively, X is "right"-totally bounded if and only if it satisfies the definition for topological abelian groups above, using "right" translates. That is, use Eai in place of E + ai. (In other words, a "size" here is unambiguously a neighbourhood of the identity element, but there are two notions of "whether" a set is of a given size: a left notion based on left translation and a right notion based on right translation.)Generalising the above definitions, a subset S of a
uniform space X is totally bounded if and only if, given any entourage E in X, there exists a finite cover of S by subsets of X each of whoseCartesian square s is a subset of E. (In other words, a "size" here is an entourage, and a subset is of size E if its Cartesian square is a subset of E.) Equivalently, S is totally bounded if and only if, given any E as before, there exist subsets A1, A2, ..., An of X such S is contained in the union of the Ai and, whenever the elements x and y of X both belong to the same set Ai, then (x,y) belongs to E (so that x and y are close as measured by E).The definition can be extended still further, to any category of spaces with a notion of compactness and
Cauchy completion : a space is totally bounded if and only if its completion is compact.Examples and nonexamples
* A subset of the
real line , or more generally of (finite-dimensional)Euclidean space , is totally bounded if and only if it is bounded.
* Theunit ball in aHilbert space , or more generally in aBanach space , is totally bounded if and only if the space has finite dimension.
* Everycompact set is totally bounded, whenever the concept is defined.
* Every totally bounded metric space is bounded. However not every bounded metric space is totally bounded.
* A subset of acomplete metric space is totally bounded if and only if it is relatively compact (meaning that its closure is compact).
* In alocally convex space endowed with the weak topology the precompact sets are exactly the bounded sets.
* A metric space is separable if and only if it is homeomorphic to a totally bounded metric space.
* An infinite metric space with thediscrete metric (the distance between any twodistinct points is 1) is "not" totally bounded, even though it is bounded.Relationships with compactness and completeness
There is a nice relationship between total boundedness and compactness: A uniform space is compact
if and only if it is both totally bounded andCauchy complete . This can be seen as a generalisation of theHeine-Borel theorem fromEuclidean space s to arbitrary spaces: we must replace boundedness with total boundedness (and also replace closedness with completeness).There is a complementary relationship between total boundedness and the process of
Cauchy completion : A uniform space is totally bounded if and only if its Cauchy completion is totally bounded. (This corresponds to the fact that, in Euclidean spaces, a set is bounded if and only if its closure is bounded.)Combining these theorems, a uniform space is totally bounded if and only if its completion is compact. This may be taken as an alternative definition of total boundedness. Alternatively, this may be taken as a definition of "precompactness", while still using a separate definition of total boundedness. Then it becomes a theorem that a space is totally bounded if and only if it is precompact. (Separating the definitions in this way is useful in the absence of the
axiom of choice ; see the next section.)Use of the axiom of choice
The properties of total boundedness mentioned above rely in part on the
axiom of choice . In the absence of the axiom of choice, total boundedness and precompactness must be distinguished. That is, we define total boundedness in elementary terms but define precompactness in terms of compactness and Cauchy completion. It remains true (that is, the proof does not require choice) that every precompact space is totally bounded; in other words, if the completion of a space is compact, then that space is totally bounded. But it is no longer true (that is, the proof requires choice) that every totally bounded space is precompact; in other words, the completion of a totally bounded space might not be compact in the absence of choice.References
*cite book | author=Willard, Stephen | title=General Topology | publisher=Dover Publications | year=2004 | id=ISBN 0-486-43479-6
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