1959 NBA Playoffs

The 1959 NBA Playoffs was the postseason tournament of the National Basketball Association's 1958-1959 season. The tournament concluded with the Eastern Conference champion Boston Celtics defeating the Western Conference champion Minneapolis Lakers, four games to none in the NBA Finals. It was the Celtics' second NBA championship.

This was the first NBA Finals matchup between the Lakers and Celtics; as of 2008 the franchises have met in the championship series 11 times. Boston won the first eight NBA Finals series of the rivalry, spanning three decades-- the 1950s, 1960s and 1980s-- before the Lakers finally defeated the Celtics for the title in 1985 and again in 1987, with Boston topping the Lakers again in 2008. "See also: Lakers-Celtics rivalry"

This was also the only Celtics/Lakers NBA Finals series that would take place while the latter team was based in Minneapolis. Indeed, the Lakers would only remain in Minneapolis one more year before moving to their current home of Los Angeles.

3RoundBracket-Byes | RD1= Division Semifinals
RD2= Division Finals
RD3= NBA Finals
group1=Western Division
group2=Eastern Division

RD1-seed1=
RD1-team1=
RD1-score1=
RD1-seed2=
RD1-team2=
RD1-score2=

RD1-seed3=3
RD1-team3=Detroit
RD1-score3=1
RD1-seed4=2
RD1-team4=Minneapolis
RD1-score4=2

RD1-seed5=
RD1-team5=
RD1-score5=
RD1-seed6=
RD1-team6=
RD1-score6=

RD1-seed7=3
RD1-team7=Syracuse
RD1-score7=2
RD1-seed8=2
RD1-team8=New York
RD1-score8=0

RD2-seed1=1
RD2-team1=St. Louis
RD2-score1=2
RD2-seed2=2
RD2-team2=Minneapolis
RD2-score2=4

RD2-seed3=1
RD2-team3=Boston
RD2-score3=4
RD2-seed4=3
RD2-team4=Syracuse
RD2-score4=3

RD3-seed1=W2
RD3-team1=Minneapolis
RD3-score1=0
RD3-seed2=E1
RD3-team2=Boston
RD3-score2=4

External links

* [http://www.basketball-reference.com/playoffs/NBA_1959.html Basketball-Reference.com's 1959 NBA Playoffs page]