- Dynamic perfect hashing
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In computer science, dynamic perfect hashing is a programming technique for resolving collisions in a hash table data structure.[1][2][3] This technique is useful for situations where fast queries, insertions, and deletions must be made on a large set, S, of elements.
Details
In this method, the entries that hash to the same slot of the table are organized as separate second-level hash table. If there are k entries in this set S, the second-level table is allocated with k2 slots, and its hash function is selected at random from a universal hash function set so that it is collision-free (i.e. a perfect hash function). Therefore, the look-up cost is guaranteed to be O(1) in the worst-case.[2]
function Locate(x) is j = h(x); if (position hj(x) of subtable Tj contains x (not deleted)) return (x is in S); end if else return (x is not in S); end else end
Although each second-level table requires quadratic space, if the keys inserted into the first-level hash table are uniformly distributed, the structure as a whole occupies expected O(n) space, since bucket sizes are small with high probability.[1]
During the insertion of a new entry x at j, the global operations counter, count, is incremented. If x exists at j but is marked as deleted then the mark is removed. If x exists at j, or at the subtable Tj, but is not marked as deleted then a collision is said to occur and the jth bucket's second-level table Tj is rebuilt with a different randomly-selected hash function hj. Because the load factor of the second-level table is kept low (1/k), rebuilding is infrequent, and the amortized cost of insertions is O(1).[2]
function Insert(x) is count = count + 1; if (count > M) FullRehash(x); end if else j = h(x); if (Position hj(x) of subtable Tj contains x) if (x is marked deleted) remove the delete marker; end if end if else bj = bj + 1; if (bj <= mj) if position hj(x) of Tj is empty store x in position hj(x) of Tj; end if else Put all unmarked elements of Tj in list Lj; Append x to list Lj; bj = length of Lj; repeat hj = randomly chosen function in Hsj; until hj is injective on the elements of Lj; for all y on list Lj store y in position hj(y) of Tj; end for end else end if else mj = 2 * max{1, mj}; sj = 2 * mj * (mj - 1); if the sum total of all sj ≤ 32 * M2 / s(M) + 4 * M Allocate sj cells for Tj; Put all unmarked elements of Tj in list Lj; Append x to list Lj; bj = length of Lj; repeat hj = randomly chosen function in Hsj; until hj is injective on the elements of Lj; for all y on list Lj store y in position hj(y) of Tj; end for end if else FullRehash(x); end else end else end else end else end
Deletion of x simply flags x as deleted without removal and increments count. In the case of both insertions and deletions, if count reaches a threshold M the entire table is rebuilt, where M is some constant multiple of the size of S at the start of a new phase. Here phase refers to the time between full rebuilds. The amortized cost of delete is O(1).[2] Note that here the -1 in "Delete(x)" is a representation of an element which is not in the set of all possible elements U.
function Delete(x) is count = count + 1; j = h(x); if position h(x) of subtable Tj contains x mark x as deleted; end if else return (x is not a member of S); end else if (count >= M) FullRehash(-1); end if end
A full rebuild of the table of S first starts by removing all elements marked as deleted and then setting the next threshold value M to some constant multiple of the size of S. A hash function, which partitions S into s(M) subsets, where the size of subset j is sj, is repeatedly randomly chosen until:
Finally, for each subtable Tj a hash function hj is repeatedly randomly chosen from Hsj until hj is injective on the elements of Tj. The expected time for a full rebuild of the table of S with size n is O(n).[2]
function FullRehash(x) is Put all unmarked elements of T in list L; if (x is in U) append x to L; end if count = length of list L; M = (1 + c) * max{count, 4}; repeat h = randomly chosen function in Hs(M); for all j < s(M) form a list Lj for h(x) = j; bj = length of Lj; mj = 2 * bj; sj = 2 * mj * (mj - 1); end for until the sum total of all sj ≤ 32 * M2 / s(M) + 4 * M for all j < s(M) Allocate space sj for subtable Tj; repeat hj = randomly chosen function in Hsj; until hj is injective on the elements of list Lj; end for for all x on list Lj store x in position hj(x) of Tj; end for end
References
- ^ a b Fredman, M. L., Komlós, J., and Szemerédi, E. 1984. Storing a Sparse Table with 0(1) Worst Case Access Time. J. ACM 31, 3 (Jun. 1984), 538-544 http://portal.acm.org/citation.cfm?id=1884#
- ^ a b c d e Dietzfelbinger, M., Karlin, A., Mehlhorn, K., Meyer auf der Heide, F., Rohnert, H., and Tarjan, R. E. 1994. Dynamic Perfect Hashing: Upper and Lower Bounds. SIAM J. Comput. 23, 4 (Aug. 1994), 738-761. http://portal.acm.org/citation.cfm?id=182370#
- ^ Erik Demaine, Jeff Lind. 6.897: Advanced Data Structures. MIT Computer Science and Artificial Intelligence Laboratory. Spring 2003. http://courses.csail.mit.edu/6.897/spring03/scribe_notes/L2/lecture2.pdf
Categories:- Hashing
- Search algorithms
- Computer programming stubs
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