1990 Atlantic 10 Men's Basketball Tournament

The 1990 Atlantic 10 Men's Basketball Tournament was played from March 3 to March 5, 1990 and March 8, 1990, at the Palestra in Philadelphia, Pennsylvania, except for the final that was played at McGonigle Hall in Philadelphia. The winner was named champion of the Atlantic 10 Conference and received an automatic bid to the 1990 NCAA Men's Division I Basketball Tournament. Temple University won the tournament. No other teams received bids to the NCAA Tournament. The top six teams in the conference received first-round byes.

Bracket

4RoundBracket-Byes
RD1=First Round March 3 Palestra, Philadelphia, PA
RD2=Quarterfinals March 4 Palestra
RD3=Semifinals March 5 Palestra
RD4=Final March 8 McGonigle Hall, Philadelphia
group1=
group2=

RD1-seed03=8
RD1-team03=Saint Joseph's
RD1-score03=70
RD1-seed04=9
RD1-team04=Duquesne
RD1-score04=96

RD1-seed11=7
RD1-team11=George Washington
RD1-score11=85
RD1-seed12=10
RD1-team12=St. Bonaventure
RD1-score12=77

RD2-seed01=1
RD2-team01=Temple
RD2-score01=61
RD2-seed02=9
RD2-team02=Duquesne
RD2-score02=50

RD2-seed03=4
RD2-team03=Rhode Island
RD2-score03=79
RD2-seed04=5
RD2-team04=Rutgers
RD2-score04=80

RD2-seed05=2
RD2-team05=Penn State
RD2-score05=83
RD2-seed06=7
RD2-team06=George Washington
RD2-score06=72

RD2-seed07=3
RD2-team07=West Virginia
RD2-score07=55
RD2-seed08=6
RD2-team08=Massachusetts
RD2-score08=78

RD3-seed01=1
RD3-team01=Temple
RD3-score01=65
RD3-seed02=5
RD3-team02=Rutgers
RD3-score02=57

RD3-seed03=2
RD3-team03=Penn State
RD3-score03=59
RD3-seed04=6
RD3-team04=Massachusetts
RD3-score04=64

RD4-seed01=1
RD4-team01=Temple
RD4-score01=53
RD4-seed02=6
RD4-team02=Massachusetts
RD4-score02=51