- Quadratic irrational
In
mathematics , a quadratic irrational, also known as a quadratic irrationality or quadratic surd, is anirrational number that is the solution to somequadratic equation with rational coefficients. Since fractions can be cleared from a quadratic equation by multiplying both sides by theircommon denominator , this is the same as saying it is an irrational root of some quadratic equation whose coefficients areinteger s. They form thereal number subset of thealgebraic numbers of degree 2. The quadratic irrationals, therefore, are all those numbers that can be expressed in this form::
for
integers "a", "b", "c", "d"; with "b" and "d" non-zero, and with "c">1 andsquare free . This implies that the quadratic irrationals have the samecardinality as ordered quadruples of integers, and are thereforecountable .The quadratic irrationals with a given "c" form a
field , called aquadratic field .Quadratic irrationals have useful properties, especially in relation to
continued fraction s, where we have the result that "all" quadratic irrationals, and "only" quadratic irrationals, have periodic continued fraction forms. For example:quare root of non-square is irrational
The square root of any natural number that is not a square is irrational. The
square root of 2 was the first to be proved irrational.Theodorus of Cyrene proved the irrationality of the surds of whole numbers up to 17, but stopped there, probably because the algebra he used couldn't be applied to the square root of 17. Euclid's Elements Book 10 is dedicated to classification of irrational magnitudes. The original proof of the irrationality of the non-square natural numbers depends onEuclid's lemma .Many people when they try to prove the irrationality of the non-square natural numbers implicitly assume the
fundamental theorem of arithmetic which was first proven byCarl Friedrich Gauss in hisDisquisitiones Arithmeticae .The following proof by
Richard Dedekind assumes nothing more than the ordering of the natural numbers and makes no use of prime numbers. [ [http://www.cut-the-knot.org/proofs/sq_root.shtml Cut the knot: Square root of 2 is irrational] ] Like most proofs of this theorem it usesrecursive descent .Assume D is a non square natural number then there is a number n such that:
:n2 < D < (n+1)2
Assume the square root of D is a rational number p/q, assume the q here is the smallest for which this is true, then:
:Dq2 = p2
Multiplying through by q2 we get
:n2q2 < Dq2 < (n+1)2q2
then substituting for the middle term and removing the squares:
:nq < p < (n+1)q
Let s = p-nq then 0 < s < q
Furthermore multiplying through by p2 we get:
:n2p2 < Dp2 < (n+1)2p2
again substituting for the middle term and removing the squares we get:
:np < Dq < (n+1)p
Let r = Dq-np then 0 < r < p
Then we get to the recursive descent part of the proof
:Ds2 - r2 = D(p-nq)2 - (Dq-np)2 = Dp2 - 2Dnpq + Dn2q2 - D2q2 + 2Dnpq - n2p2
Using Dq2 = p2 three times this all disappears so we get
:Ds2 - r2 = 0
But s is greater than zero and less than q which contradicts the assumption about q and the result follows by
reductio ad absurdum .ee also
*
Algebraic number field
*Periodic continued fraction
*Restricted partial quotients External links
*mathworld|QuadraticSurd
* [http://www.numbertheory.org/php/surd.html Continued fraction calculator for quadratic irrationals]
* [http://planetmath.org/encyclopedia/EIsIrrational.html Proof that e is not a quadratic irrational]References
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