:where denotes the diameter of . Then there exists a subcollection , , of balls from our original collection which are disjoint and
::
Proof
The proof of the finite version is rather easy. With no loss of generality, we assume that the collection of balls is not empty; that is, . Let be the ball of largest radius. Inductively, assume that have been chosen. If there is some ball in that is disjoint from , let be such ball with maximal radius (breaking ties arbitrarily), otherwise, we set and terminate the inductive definition.
Now set . It remains to show that for every . This is clear if . Otherwise, there necessarily is some such that intersects and the radius of is at least as large as that of . The triangle inequality then easily implies that , as needed. This completes the proof of the finite version.
We now prove the infinite version. Let be the supremum of the radii of balls in and let be the collection of balls in whose radius is in . We first take a maximal disjoint subcollection of , then take a maximal subcollection of that is disjoint and disjoint from . Inductively, we take to be a maximal disjoint and disjoint from subcollection of . It is easy to check that the collection satisfies the requirements.
Applications and method of use
An application of the Vitali lemma is in proving the Hardy-Littlewood maximal inequality. As in this proof, the Vitali lemma is frequently used when we are, for instance, considering the Lebesgue measure, , of a set , which we know is contained in the union of a certain collection of balls , each of which has a measure we can more easily compute, or has a special property one would like to exploit. Hence, if we compute the measure of this union, we will have an upper bound on the measure of . However, it is difficult to compute the measure of the union of all these balls if they overlap. By the Vitali lemma, we may choose a subcollection which is disjoint and such that . Therefore,
:
Now, since increasing the radius of a d-dimensional ball by a factor of five increases its volume by a factor of , we know that
:
and thus
:
One may also have a similar objective when considering Hausdorff measure instead of Lebesgue measure. In that case, we have the theorem below.
Vitali covering theorem
For a set "E" ⊆ R"d", a Vitali class or Vitali covering for "E" is a collection of sets such that, for every "x" ∈ "E" and "δ" > 0, there is a set such that "x" ∈ "U" and the diameter of "U" is non-zero and less than "δ".
Theorem. Let "H""s" denote "s"-dimensional Hausdorff measure, let "E" ⊆ R"d" be an "H""s"-measurable set and a Vitali class for "E". Then there exists a (finite or countably infinite) disjoint subcollection such that either
:
Furthermore, if "E" has finite "s"-dimensional measure, then for any "ε" > 0, we may choose this subcollection {"U""j"} such that
:
Infinite-dimensional spaces
The Vitali covering theorem is not valid in infinite-dimensional settings. The first result in this direction was given by David Preiss in 1979: there exists a Gaussian measure "γ" on an (infinite-dimensional) separable Hilbert space "H" so that the Vitali covering theorem fails for ("H", Borel("H"), "γ"). This result was strengthened in 2003 by Jaroslav Tišer: the Vitali covering theorem in fact fails for "every" infinite-dimensional Gaussian measure on any (infinite-dimensional) separable Hilbert space.
References
* cite book
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first = Kenneth J.
title = The geometry of fractal sets
series = Cambridge Tracts in Mathematics 85
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* cite journal
last = Preiss
first = David
title = Gaussian measures and covering theorems
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* cite book
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* cite journal
last = Tišer
first = Jaroslav
title = Vitali covering theorem in Hilbert space
journal = Trans. Amer. Math. Soc.
volume = 355
year = 2003
number = 8
pages = 3277–3289 (electronic)
issn = 0002-9947
doi = 10.1090/S0002-9947-03-03296-3 MathSciNet|id=1974687